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HOUGHTON MIFFLIN HARCOURT GO MATH! Grade 4 Online Resources

Textbook: HOUGHTON MIFFLIN HARCOURT GO MATH! Grade 4 ISBN: 9780547587837

Use the table below to find videos, mobile apps, worksheets and lessons that supplement HOUGHTON MIFFLIN HARCOURT GO MATH! Grade 4 book.

Place Value and Operations with Whole Numbers

Place value, addition, and subtraction to one million.

Domains Number and Operations in Base Ten

Common Core Standards CC.4.NBT.1, CC.4.NBT.2, CC.4.NBT.3, CC.4.NBT.4

Model Place Value Relationships

Read and write numbers, compare and order numbers, round numbers, add whole numbers, subtract whole numbers, comparison problems with addition and subtraction, multiply by 1-digit numbers.

Domains Operations and Algebraic Thinking

Common Core Standards CC.4.OA.1, CC.4.OA.2, CC.4.OA.3, CC.4.NBT.5

Multiplication Comparisons

Comparison problems, multiply tens, hundreds, and thousands, estimate products, multiply using the distributive property, multiply using expanded form, multiply using partial products, multiply using mental math, multistep multiplication problems, multiply 2-digit numbers with regrouping, multiply 3-digit and 4-digit numbers with regrouping, solve multistep problems using equations, multiply 2-digit numbers.

Domains Operations and Algebraic Thinking Number and Operations in Base Ten

Common Core Standards CC.4.OA.3, CC.4.NBT.5

Multiply by Tens

Area models and partial products, multiply with regrouping, choose a multiplication method, divide by 1-digit numbers.

Domains Operations and Algebraic Thinking Numbers and Operations in Base Ten

Common Core Standards CC.4.OA.3, CC.4.NBT.6

Estimate Quotients Using Multiples

Interpret remainders, divide tens, hundreds, and thousands, estimate quotients using compatible numbers, division and the distributive property, divide using repeated subtraction, divide using partial quotients, model division with regrouping, place the first digit, multistep division problems, factors, multiples, and patterns.

Common Core Standards CC.4.OA.4, CC.4.OA.5

Model Factors

Factors and divisibility, common factors, factors and multiples, prime and composite numbers, number patterns, fractions and decimals, fractions equivalent and comparison.

Domains Number and Operations-Fractions

Common Core Standards CC.4.NF.1, CC.4.NF.2

Equivalent Fractions

Generate equivalent fractions, simplest form, common denominators, find equivalent fractions, compare fractions using benchmarks, compare fractions, compare and order fractions, add and subtract fractions.

Domains Numbers and Operations-Fractions

Common Core Standards CC.4.NF.3a, CC.4.NF.3b, CC.4.NF.3c, CC.4.NF.3d

Add and Subtract Parts of a Whole

Write fractions as sums, add fractions using models, subtract fractions using models, subtraction with renaming, fractions and properties of addition, multistep fraction problems, multiply fractions by whole numbers.

Domains Numbers and Operations – Fractions

Common Core Standards CC.4.NF.4a, CC.4.NF.4b, CC.4.NF.4c

Multiples of Unit Fractions

Multiples of fractions, multiply a fraction by a whole number using models, multiply a fraction or mixed numbers by a whole number, comparison problems with fractions, related fractions and decimals.

Domains Numbers and Operations – Fractions Measurement and Data

Common Core Standards CC.4.NF.5, CC.4.NF.6, CC.4.NF.7, CC.4.MD.2

Relate Tenths with Decimals

Relate hundredths with decimals, equivalent fractions with decimals, relate fractions, decimals, and money, add fractional parts of 10 and 100, compare decimals, geometry, measurement, and data, two-dimensional figures.

Domains Operations and Algebraic Thinking Geometry

Common Core Standards CC.4.OA.5, CC.4.G.1, CC.4.G.2, CC.4.G.3

Lines, Rays, and Angles

Classify triangles, parallel lines and perpendicular lines, classify quadrilaterals, line symmetry, find and draw lines of symmetry, shape patterns.

Domains Measurement and Data

Common Core Standards CC.4.MD.5a, CC.4.MD.5b, CC.4.MD.6, CC.4.MD.7

Angles and Fractional Parts of a Circle

Measure and draw angles, join and separate angles, unknown angles measure, related size of measurement units.

Common Core Standards CC.4.MD.1, CC.4.MD.2, CC.4.MD.4

Measurement Benchmarks

Customary units of length, customary units of weight, customary units of liquid volume, metric units of volume, metric units of mass and liquid volume, units of time, elapsed time, mixed measure, patterns in measurement units, algebra: perimeter and area.

Common Core Standards CC.4.MD.3

Area of Combined Rectangles

Find unknown measures, find the area.

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go math grade 4 chapter 10 homework

4th Grade Go Math- Chapter 10 Classwork/Homework

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This resource is closely aligned to the 4th Grade Go Math Chapter 10 lessons. I use this resource as an independent classwork station after students meet with me during teacher-guided instruction. This resource could easily be used as homework as well. It takes the main concept/skill from each lesson and puts it into a one-page practice. Many of the problems are taken directly from the Go Math homework pages.

One thing to note:

* I combined Lesson 10.5 and Lesson 10.6 into a one page practice on symmetry

Make sure to check out my word problem resource to supplement your curriculum. This resource is designed to enhance student learning and mathematical understanding!

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These are the chapters for the CURRENT COMMON CORE math books

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Go Math Grade 4 Answer Key Chapter 13 Algebra: Perimeter and Area

Students who are looking for a great study resource or prep resource can refer to this page. Here, we have curated a Grade 4 Answer Key of Go Math Chapter 13 Algebra: Perimeter and Area. Download HMH Go Math Grade 4 Answer Key Chapter 13 Algebra: Perimeter and Area pdf by accessing the links available over here. Save them and use the Go Math Grade 4 Answer Key Chapter 13 Algebra: Perimeter and Area as a reference purpose during your practice sessions & score good marks in the exam.

Students can find various concepts questions and solutions covered in the chapter 13 Algebra: Perimeter and Area from this Go math Gerade 4 Answer Keys. All these solutions are prepared by the subject experts in a well-organized and understanding manner. So, practice all exercise and homework problems through Go Math 4th Grade Key of Chapter 13 Perimeter and Area. Also, test your knowledge by answering the given sums and learn your mistakes using HMH Go Math Grade 4 Solution Key Chapter Perimeter and Area.

Common Core – New – Page No. 721

Find the perimeter of the rectangle or square.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 1

Explanation:

Length = 9 inches Width = 3 inches Perimeter of the rectangle = l + w + l + w 9+3+9+3=24 Therefore the Perimeter of the rectangle = 24 inches.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 2

Answer: 32 meters

Side of a square = 8 meters The perimeter of a square = 4a = 4 × 8 meters = 32 meters Thus the perimeter of a square = 32 meters.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 3

Answer: 44 feet

Length = 10 ft Width = 12 ft Perimeter of the rectangle = l + w + l + w P = 10 + 12 + 10 + 12 = 20 + 24 = 44 feets Thus the perimeter of the rectangle = 44 feet.

Remember: perimeter is the total distance around the outside, which can be found by adding together the length of each side. In the case of a rectangle, opposite sides are equal in length, so the perimeter is twice its width plus twice its height.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 4

Answer: 108 centimeters

Length = 30 cm Width = 24 cm Perimeter of the rectangle = l + w + l + w = 30 + 24 + 30 + 24 = 60 + 48 = 108 centimeters Therefore the perimeter of the rectangle = 108 centimeters

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 5

Answer: 216 inches

Length = 25 in. Width = 83 in. Perimeter of the rectangle = l + w + l + w = 25 + 83 + 25 + 83 = 216 inches Thus the perimeter of the rectangle = 216 inches

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 6

Answer: 240 meters

The side of a square = 60 meters The perimeter of the square = 4a = 4 × 60 meters = 240 meters Thus the perimeter of the square = 240 meters.

Problem Solving

Question 7. Troy is making a flag shaped like a square. Each side measures 12 inches. He wants to add ribbon along the edges. He has 36 inches of ribbon. Does he have enough ribbon? Explain. _____

Answer: No. He needs 48 inches of ribbon.

Troy is making a flag shaped like a square. Each side measures 12 inches. He wants to add a ribbon along the edges. He has 36 inches of ribbon. 36 inches + 12 inches = 48 inches

Question 8. The width of the Ochoa Community Pool is 20 feet. The length is twice as long as its width. What is the perimeter of the pool? _____ feet

Answer: 120 feet

The width of the Ochoa Community Pool is 20 feet. The length is twice as long as its width. Length = 2 × 20 feet = 40 feet Perimeter of the rectangle = l + w + l + w = 40 + 20 + 40 + 20 = 120 feet Thus the perimeter of the pool is 120 feet.

Common Core – New – Page No. 722

Lesson Check

Question 1. What is the perimeter of a square window with sides 36 inches long? Options: a. 40 inches b. 72 inches c. 144 inches d. 1,296 inches

Answer: 144 inches

Given, Side of a square = 36 inches The perimeter of the square = 4 × side = 4a = 4 × 36 inches = 144 inches Thus the perimeter of the square = 144 inches The correct answer is option C.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 7

Answer: 18 meters

Length of the rectangle = 5 meter Width of the rectangle = 4 meters The perimeter of the rectangle = l + w + l + w = 5 + 4 + 5 + 4 = 18 meters Thus the correct answer is option C.

Spiral Review

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 8

Answer: 90°

By seeing the above figure we can say that it is the right angle. The correct answer is option B.

Question 4. Ethan has 3 pounds of mixed nuts. How many ounces of mixed nuts does Ethan have? Options: a. 30 ounces b. 36 ounces c. 48 ounces d. 54 ounces

Answer: 48 ounces

Given that, Ethan has 3 pounds of mixed nuts. 1 pound = 16 ounces 3 pounds = 3 × 16 ounces = 48 ounces Therefore the correct answer is option C.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 9

The above shape has 1 line of symmetry. The correct answer is option B.

Question 6. Which of the following comparisons is correct? Options: a. 0.70 > 7.0 b. 0.7 = 0.70 c. 0.7 < 0.70 d. 0.70 = 0.07

Answer: 0.7 = 0.70

a. 0.70 > 7.0 7.0 = 7 0.7 is less than 7

b. 0.7 = 0.70 0.7 is nothing but 0.70 So, the comparision is correct. The answer is option B.

Page No. 725

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 10

Answer: 143 square cm

Length = 11 cm Width = 13 cm Area of the rectangle = l × w = 11 cm × 13 cm = 143 square cm Therefore the area of the rectangle = 143 square cm

Find the area of the rectangle or square.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 11

Answer: 14 square inches

Length = 7 inches Width = 2 inches Area of the rectangle = l × w = 7 inches × 2 inches = 14 inches Therefore the area of the rectangle = 14 square inches

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 12

Answer: 81 square meters

Side of the square = 9 m Area of a square = s × s = 9 m × 9 m = 81 square meters Thus the area of a square = 81 square meters

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 13

Answer: 112 square feet

Length = 8 feet Width = 14 feet Area of the rectangle = l × w = 8 feet × 14 feet = 112 square feet Therefore, area of the rectangle = 112 square feet

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 14

Answer: 65 square feet

Length of the rectangle = 13 ft Width of the rectangle = 5 feet Area of a rectangle = l × w = 13 feet × 5 feet = 65 square feet Thus, the area of the rectangle = 65 square feet

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 15

Answer: 169 square yards

Side of the square = 13 yards Area of a square = s × s = 13 yards × 13 yards = 169 square yards Therefore, the area of a square = 169 square yards

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 16

Answer: 40 square centimeters

Length of the rectangle = 20 cm Width of the rectangle = 2 cm Area of a rectangle = l × w = 20 cm × 2 cm = 40 square centimeters Therefore the area of the rectangle = 40 square centimeters.

Practice: Copy and Solve Find the area of the rectangle.

Question 8. base: 16 feet height: 6 feet A = _____ square feet

Answer: 96 square feet

base: 16 feet height: 6 feet Area of a rectangle = b ×h = 16 feet × 6 feet = 96 square feet Thus the area of the rectangle = 96 square feet

Question 9. base: 9 yards height: 17 yards A = _____ square yards

Answer: 153 square yards

base: 9 yards height: 17 yards Area of a rectangle = b × h 9 yards × 17 yards = 153 square yards The area of the rectangle = 153 square yards

Question 10. base: 14 centimeters height: 11 centimeters A = _____ square centimeters

Answer: 154 square centimeters

base: 14 centimeters height: 11 centimeters Area of a rectangle = b × h 14 centimeters × 11 centimeters = 154 square centimeters The area of the rectangle = 154 square centimeters

Question 11. Terry’s rectangular yard is 15 meters by 18 meters. Todd’s rectangular yard is 20 meters by 9 meters. How much greater is the area of Terry’s yard than Todd’s yard? _____ square meters

Answer: 90 square meters

Given, Terry’s rectangular yard is 15 meters by 18 meters. Todd’s rectangular yard is 20 meters by 9 meters. Terry’s rectangular yard: Area of a rectangle = b × h = 15 meters × 18 meters = 270 square meters Todd’s rectangular yard: Area of a rectangle = b × h 20 meters × 9 meters = 180 square meters 270 square meters – 180 square meters = 90 square meters Terry’s yard is 90 square meters greater than Todd’s yard.

Question 12. Reason Quantitatively Carmen sewed a square baby quilt that measures 36 inches on each side. What is the area of the quilt? A = _____ square inches

Answer: 1296 square inches

Carmen sewed a square baby quilt that measures 36 inches on each side. Area of a square = s × s = 36 inches × 36 inches = 1296 square inches Therefore the area of the quilt is 1296 square inches.

Page No. 726

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 17

Question 13. Nancy and Luke are drawing plans for rectangular flower gardens. In Nancy’s plan, the garden is 18 feet by 12 feet. In Luke’s plan, the garden is 15 feet by 15 feet. Who drew the garden plan with the greater area? What is the area? a. What do you need to find? Type below: __________

Answer: I need to find who drew the garden plan with the greater area.

Question 13. b. What formula will you use? Type below: __________

Answer: I will Area of rectangle and Area of a square formula

Question 13. c. What units will you use to write the answer? Type below: __________

Answer: Square feet units

Question 13. d. Show the steps to solve the problem. Type below: __________

Answer: First, we need to find the area of Nancy’s plan Length = 18 feet Width = 12 feet Area of a rectangle = l × w A = 18 feet × 12 feet = 216 square feet And now we need to find the area of Luke’s plan A = s × s A = 15 feet × 15 feet = 225 square feet

Question 13. e. Complete the sentences. The area of Nancy’s garden is _______. The area of Luke’s garden is _______. _______ garden has the greater area. Type below: __________

Answer: The area of Nancy’s garden is 216 square feet. The area of Luke’s garden is 225 square feet. Luke’s garden has a greater area.

Question 14. Victor wants to buy fertilizer for his yard. The yard is 35 feet by 55 feet. The directions on the bag of fertilizer say that one bag will cover 1,250 square feet. How many bags of fertilizer should Victor buy to be sure that he covers the entire yard? ______ bags

Answer: 2 bags

Explanation: Given that, Victor wants to buy fertilizer for his yard. The yard is 35 feet by 55 feet. The directions on the bag of fertilizer say that one bag will cover 1,250 square feet. A = b × h A = 35 feet × 55 feet A = 1925 square feet 1925 square feet is greater than 1,250 square feet. So, Victor has to buy 2 bags to be sure that he covers the entire yard.

Question 15. Tuan is an artist. He is painting on a large canvas that is 45 inches wide. The height of the canvas is 9 inches less than the width. What is the area of Tuan’s canvas? A = ______ square inches

Answer: 1620 square inches

Explanation: Tuan is an artist. He is painting on a large canvas that is 45 inches wide. The height of the canvas is 9 inches less than the width. So, h = 45 – 9 = 36 inches A = b × h A = 45 inches × 36 inches A = 1,620 square inches Therefore the area of Tuan’s canvas is 1620 square inches.

Common Core – New – Page No. 727

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 18

Answer: 64 square yards

Side of the square = 8 yards Area of the square = s × s 8 yards × 8 yards = 64 square yards Therefore, The area of the square is 64 square yards.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 20

Answer: 45 square meters

Length of the rectangle = 15 m Width of the rectangle = 3 m Area of the rectangle = b × h = 15 m × 3 m = 45 square meters Thus the area of the rectangle is 45 square meters.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 21

Answer: 78 square inches

The base of the rectangle = 13 in. Height of the rectangle = 6 in. Area of the rectangle = b × h 13 in. × 6 in. = 78 square inches Thus the area of the rectangle is 78 square inches.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 22

Answer: 150 square centimeters

The base of the rectangle = 30 cm Height of the rectangle = 5 cm Area of the rectangle = b × h 30 cm × 5 cm = 150 square centimeters Therefore, the area of the rectangle = 150 square centimeters

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 23

Answer: 56 square feet

The base of the rectangle = 14 feet Height of the rectangle = 4 feet Area of the rectangle = b × h 14 feet × 4 feet = 56 square feet Therefore, the area of the rectangle = 56 square feet.

Question 7. Meghan is putting wallpaper on a wall that measures 8 feet by 12 feet. How much wallpaper does Meghan need to cover the wall? ______ square feet wallpaper

Meghan is putting wallpaper on a wall that measures 8 feet by 12 feet. The base of the rectangle = 8 feet Height of the rectangle = 12 feet Area of the rectangle = b × h 8 feet × 12 feet = 96 square feet Thus the Area of the rectangle = 96 square feet

Question 8. Bryson is laying down sod in his yard to grow a new lawn. Each piece of sod is a 1-foot by 1-foot square. How many pieces of sod will Bryson need to cover his yard if his yard measures 30 feet by 14 feet? ______ pieces

Answer: 420 pieces

Bryson is laying down sod in his yard to grow a new lawn. Each piece of sod is a 1-foot by 1-foot square. The base of the rectangle = 30 feet Height of the rectangle = 14 feet Area of the rectangle = b × h = 30 feet × 14 feet = 420 sq. ft. Therefore Bryson needs 420 pieces of sod to cover his yard.

Common Core – New – Page No. 728

Question 1. Ellie and Heather drew floor models of their living rooms. Ellie’s model represented 20 feet by 15 feet. Heather’s model represented 18 feet by 18 feet. Whose floor model represents the greater area? How much greater? Options: a. Ellie; 138 square feet b. Heather; 24 square feet c. Ellie; 300 square feet d. Heather; 324 square feet

Answer: Heather; 24 square feet

Given, Ellie and Heather drew floor models of their living rooms. Ellie’s model represented 20 feet by 15 feet. Heather’s model represented 18 feet by 18 feet. Area of Ellie’s model = 20 feet × 15 feet = 300 square feet Area of Heather’s model = 18 feet × 18 feet = 324 square feet Now subtract the area of Ellie’s model from Heather’s model = 324 square feet – 300 square feet = 24 square feet Thus the area of Heather’s model is greater than Ellie’s model The correct answer is option B.

Question 2. Tyra is laying down square carpet pieces in her photography studio. Each square carpet piece is 1 yard by 1 yard. If Tyra’s photography studio is 7 yards long and 4 yards wide, how many pieces of square carpet will Tyra need? Options: a. 10 b. 11 c. 22 d. 28

Tyra is laying down square carpet pieces in her photography studio. Each square carpet piece is 1 yard by 1 yard. Tyra’s photography studio is 7 yards long and 4 yards wide Area of the rectangle = b × h = 7 yards × 4 yards = 28 square yards Thus the correct answer is option D.

Question 3. Typically, blood fully circulates through the human body 8 times each minute. How many times does blood circulate through the body in 1 hour? Options: a. 48 b. 240 c. 480 d. 4,800

Answer: 480

Blood fully circulates through the human body 8 times each minute. 1 minute = 60 seconds 8 × 60 seconds = 480 seconds The correct answer is option C.

Question 4. Each of the 28 students in Romi’s class raised at least $25 during the jump-a-thon. What is the least amount of money the class raised? Options: a. $5,200 b. $700 c. $660 d. $196

Answer: $700

Each of the 28 students in Romi’s class raised at least $25 during the jump-a-thon. Multiply number od students with $25 28 × $25 = $700 The correct answer is option B.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 24

Answer: 28 feet

Given that 1 square is equal to 1 square foot There are 14 squares Length = 14 squares Width = 2 squares Area of the rectangle = l × w = 14 × 2 = 28 sq. feets The correct answer is option D.

Question 6. Ryan is making small meat loaves. Each small meat loaf uses \(\frac{3}{4}\) pound of meat. How much meat does Ryan need to make 8 small meat loaves? Options: a. 4 pounds b. 6 pounds c. 8 pounds d. 10 \(\frac{2}{3}\) pounds

Answer: 6 pounds

Ryan is making small meatloaves. Each small meatloaf uses \(\frac{3}{4}\) pound of meat. Ryan need to make 8 small meatloaves. \(\frac{3}{4}\) × 8 = 6 pounds The correct answer is option B.

Page No. 731

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 25

Answer: 23 square units

Explanation: Rectangle: Each square box = 1 unit There are 7 units Base = 7 units Height = 2 units The area of the figure = b × h A = 7 units × 2 units = 14 square units Square: The side is 3 units Area of the square = 3 units × 3 units = 9 square units Add both the areas = 14 square units + 9 square units = 23 square units Therefore the area of the above figure is 23 square units.

Find the area of the combined rectangles.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 26

Answer: 72 square mm

Explanation: Area of top rectangle = b × h Base = 12 mm Height = 3 mm A = 12 mm × 3 mm = 36 square mm Area of square = s × s s = 6 mm A = 6 mm × 6 mm = 36 square mm Area of the figure = 36 square mm + 36 square mm = 72 square mm Thus the area of the above figure is 72 square mm.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 27

Answer: 146 square miles

Explanation: Area of rectangle = b × h Area of the first rectangle = 10 mi × 9 mi A = 90 square miles Area of the second rectangle = 8 mi × 7 mi A = 56 square miles Area of the figure = Area of first rectangle + Area of the second rectangle Area of the figure = 90 square mi + 56 square miles Thus the Area of the figure = 146 square miles

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 28

Explanation: There are 2 squares and one rectangle in this figure Area of the square = s × s A = 4 ft × 4 ft = 16 square ft Area of the square = s × s A = 4 ft × 4 ft = 16 square ft Area of the rectangle = b × h A = 16 ft × 4 ft = 64 square ft Area of the figure = 16 square ft + 16 square ft + 64 square ft Thus the Area of the figure = 96 square feet.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 29

Answer: 180 square yards

There are 2 rectangles in the above figure Area of rectangle = b × h A = 12 yard × 8 yards  = 96 square yards Area of rectangle = b × h A = 6 yards × 14 yards = 84 square yards Area of the figure = 96 square yards + 84 square yards Therefore the area of the figure = 180 square yards.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 30

Answer: A = 92 square feet; P = 5 2 feet

Explanation: There are 2 rectangle in the figure Area of rectangle = b × h A = 5 ft × 4 ft = 20 square ft Area of rectangle = b × h A = 8 ft × 9 ft = 72 square ft Area of the figure = 20 square ft + 72 square ft = 92 square ft Perimeter of the rectangle = 2l + 2w P = 2 × 5 + 2 × 4 = 10 + 8 = 18 feet Perimeter of the rectangle = 2l + 2w P = 2 × 8 + 2 × 9 = 16 + 18 = 34 feet Perimeter of the figure = 52 feet

Page No. 732

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 31

Question 7. The diagram shows the layout of Mandy’s garden. The garden is the shape of combined rectangles. What is the area of the garden? a. What do you need to find? Type below: __________

Answer: I need to find the area of the garden.

Question 7. b. How can you divide the figure to help you find the total area? Type below: __________

Answer: I will divide the figure into 3 parts to find the total area

Question 7. c. What operations will you use to find the answer? Type below: __________

Answer: I will use the addition operation to find the area.

Question 7. d. Draw a diagram to show how you divided the figure. Then show the steps to solve the problem. Type below: __________

Go-Math-Grade-4-Answer-Key-Chapter-13-Algebra-Perimeter-and-Area-img-31

Answer: Yes Explanation: There are 2 rectangles in the above figure B = 2 ft H = 8 ft A = 2 × 8 B = 4 ft H = 2 ft A = 4 × 2 Thus the above statement is correct.

Question 8. 8b. 2 × 6 and 2 × 8 i. yes ii. no

Answer: No There are 2 rectangles in the above figure B = 6 ft H = 2 ft A = 2 × 6 Then 2 will be subtracted from 8 = 6 So, the above statement 2 × 6 and 2 × 8 is false.

Question 8. 8c. 2 × 6 and 6 × 2 i. yes ii. no

Answer: Yes Explanation: There are 2 rectangles in the above figure B = 6 ft H = 2 ft A = 6 × 2 B = 2 ft H = 6 ft A = 2 × 6 Thus the above statement is true.

Common Core – New – Page No. 733

Area of Combined Rectangles

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 33

Answer: 143 square feet

Go-Math-Grade-4-Answer-Key-Chapter-13-Algebra-Perimeter-and-Area-img-34

Area of A = 9 ft × 5 ft = 45 sq. ft. Area of B = 14 ft. × 7 ft. = 98 sq. ft. Total Area = Area of A + Area of B = 45 sq. ft. + 98 sq. ft. = 143 square feet Therefore the total Area = 143 square feet

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 35

Answer: 63 square inches

Go-Math-Grade-4-Answer-Key-Chapter-13-Algebra-Perimeter-and-Area-img-35

Area of A = 9 in. × 5 in. = 45 square inches Area of B = 6 inches × 3 inches = 18 square inches Total Area = Area of A + Area of B Total Area = 45 square inches + 18 square inches Total Area = 63 square inches

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 36

Answer: 50 square feet

Go-Math-Grade-4-Answer-Key-Chapter-13-Algebra-Perimeter-and-Area-img-36

Area of A = 4 feet × 2 feet = 8 square feet Area of B = 7 feet × 6 feet = 42 square feet Total Area = Area of A + Area of B Total Area = 8 square feet + 42 square feet Total Area = 50 square feet

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 37

Answer: 180 square centimeters

Go-Math-Grade-4-Answer-Key-Chapter-13-Algebra-Perimeter-and-Area-img-37

Area of A = 12 cm × 7 cm = 84 square cm Area of B = 16 cm × 6 cm = 96 square cm Total Area = Area of A + Area of B Total Area = 84 square cm + 96 square cm Total Area = 180 square centimeters

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 38

Answer: 68 square yards

Go-Math-Grade-4-Answer-Key-Chapter-13-Algebra-Perimeter-and-Area-img-38

Area of A = 14 yd × 1 yd = 14 square yards Area of B = 9 yd × 6 yd = 54 square yards Total Area = Area of A + Area of B Total Area = 14 square yards + 54 square yards Total Area = 68 square yards

Use the diagram for 7–8.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 39

Question 7. What is the area of the space that Nadia has shown for scrapbooking? ______ square feet

Answer: 52 square feet

Length = 13 feet Width = 9 feet – 5 feet = 4 feet Area of scrapbooking = l × w = 13 feet × 4 feet = 52 square feet Therefore the area of the space that Nadia has shown for scrapbooking is 52 square feet.

Question 8. What is the area of the space she has shown for painting? ______ square feet

Answer: 25 square feet

Explanation: The space for painting is a square. Side of the square is 5 feet Area of the square = 5 feet × 5 feet = 25 square feet Thus the area of the space she has shown for painting is 25 square feet.

Common Core – New – Page No. 734

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 40

Answer: 76 square yards

Explanation: Area of 1st rectangle = 5 yards × 8 yards = 40 square yards Area of 2nd rectangle = 12 yards × 3 yards = 36 square yards Area of the figure = Area of 1st rectangle + Area of 2nd rectangle Area of the figure = 40 square yards + 36 square yards Therefore, the Area of the figure is 76 square yards. So, the correct answer is option C.

Question 2. Marquis is redecorating his bedroom. What could Marquis use the area formula to find? Options: a. how much space should be in a storage box b. what length of wood is needed for a shelf c. the amount of paint needed to cover a wall d. how much water will fill up his new aquarium

Answer: the amount of paint needed to cover a wall

Question 3. Giraffes are the tallest land animals. A male giraffe can grow as tall as 6 yards. How tall would the giraffe be in feet? Options: a. 2 feet b. 6 feet c. 12 feet d. 18 feet

Answer: 18 feet

Explanation: Giraffes are the tallest land animals. A male giraffe can grow as tall as 6 yards. 6 yards + 6 yards + 6 yards = 18 yards The correct answer is option D.

Question 4. Drew purchased 3 books for $24. The cost of each book was a multiple of 4. Which of the following could be the prices of the 3 books? Options: a. $4, $10, $10 b. $4, $8, $12 c. $5, $8, $11 d. $3, $7, $14

Answer: $4, $8, $12

Explanation: Given that, Drew purchased 3 books for $24. The cost of each book was a multiple of 4. So, the prices of books will be multiple of 4. That means $4 × 1, $4 × 2, $4 × 3 =  $4, $8, $12 The correct answer is option B.

Question 5. Esmeralda has a magnet in the shape of a square. Each side of the magnet is 3 inches long. What is the perimeter of her magnet? Options: a. 3 inches b. 7 inches c. 9 inches d. 12 inches

Answer: 12 inches

Explanation: Esmeralda has a magnet in the shape of a square. Each side of the magnet is 3 inches long. Side = 3 inches The perimeter of the square = 4s P = 4 × 3 = 12 inches The correct answer is option D.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 41

Answer: 63 square feet

Explanation: Area of the rectangle = base × height Base = 9 feet Height = 7 feet A = 9 feet × 7 feet A = 63 square feet Thus the correct answer is option A.

Page No. 735

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 42

Question 1. A square that is 1 unit wide and 1 unit long is a ________. __________

Answer: Square unit

Question 2. The _______ of a two-dimensional figure can be any side. __________

Answer: Base

Question 3. A set of symbols that expresses a mathematical rule is called a ______. __________

Answer: Formula

Question 4. The ______ is the distance around a shape. __________

Answer: Perimeter

Find the perimeter and area of the rectangle or square.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 43

Answer: Perimeter = 52 cm Area = 169 square cm

Explanation: P = 4s P = 4 × 13 = 52 cm A = s × s A = 13 × 13 = 169 square cm

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 44

Answer: Perimeter: 48 ft Area = 63 square ft

Explanation: Base = 21 ft Height = 3 ft P = 2l +2w P = 2 (21 ft + 3 ft) P = 2 × 24 = 48 feet A = b × h A = 21 × 3 A = 63 square ft

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 45

Answer: Perimeter = 46 in. Area = 120 square in.

Explanation: P = 2l +2w P = 2 × 15 + 2 × 8 P = 30 + 16 = 46 inches A = l × w A = 15 × 8 = 120 square inches

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 46

Answer: Area of the rectangle = 20 yards × 5 yards = 100 square yards Area of the rectangle = 18 yards × 5 yards = 90 square yards Area of the figure = 100 square yards + 90 square yards = 190 square yards

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 47

Answer: A = b × h A = 5 m × 2 m = 10 square meters A = b × h A = 5 m × 2 m = 10 square meters A = b × h A = 4 m × 2 m = 8 square meters Now add all the areas 10 square meters + 10 square meters + 8 square meters = 28 square meters Therefore the area of the figures is 28 square meters

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 48

Page No. 736

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 49

Answer: Figure B has the highest perimeter.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 53

Answer: Figure C

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 57

Answer: Figure A

Page No. 739

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 61

Answer: 12 feet

Explanation: Given, The area of the rectangle = 36 square feet Height = 3 feet Base =? A = b × h 36 square feet = b × 3 feet b × 3 feet = 36 square feet b = 36/3 = 12 feet The base of the rectangle is 12 feets.

Find the unknown measure of the rectangle.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 62

Answer: 10 cm

Explanation: Given, Perimeter = 44 centimeters Length = 12 cm width =? The perimeter of the rectangle = 2 (l + w) P = 2l + 2w 44 cm = 24 cm + 2w 2w = 44 cm – 24 cm 2w = 20 cm w = 20/2 = 10 Therefore width = 10 cm

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 63

Explanation: Given, Area = 108 square inches Base = 9 inches height = _____ in. A = b × h 108 square inches = 9 inches × h h = 108/9 Height = 12 inches Therefore the height of the rectangle = 12 inches

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 64

Explanation: Given, Area = 90 square meters Height = 5 meters base = _____ cm A = b × h 90 square meters = b × 5 meters b × 5 meters = 90 square meters b = 90/5 = 18 meters Therefore the base of the rectangle = 18 meters

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 65

Answer: 12 yards

Explanation: Given, Perimeter = 34 yards Width = 5 yards Length =? The perimeter of the rectangle = 2 (l + w) P = 2l + 2w 34 yards = 2 × l + 2 × 5 yards 34 yards = 2 × l + 10 yards 2 × l + 10 yards = 34 yards 2l = 34 yards – 10 yards 2l = 24 yards l = 24/2 = 12 yards Therefore the length of the rectangle = 12 yards.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 66

Explanation: Given, Area = 96 square feet Height = 8 feet Base =? A = b × h 96 square feet = b × 8 feet b × 8 feet = 96 square feet b = 96/8 = 12 feet Thus base of the rectangle = 12 feet.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 67

Answer: 14 centimeters

Explanation: Given, Area = 126 square centimeters Base = 9 cm height = _____ centimeters A = b × h 126 square centimeters = 9 cm × h 9 cm × h = 126 square centimeters h = 126/9 = 14 centimeters Therefore the Height of the rectangle = 14 centimeters

Question 8. A square has an area of 49 square inches. Explain how to find the perimeter of the square. Type below: ________

Explanation: Given that, A square has an area of 49 square inches. A = 49 square inches s^2 = 49 square inches The square root of 49 is 7 So, each side of the square is 7 inches The perimeter of the square = 4 × s 4 × 7 inches = 28 inches. Therefore the perimeter of the square is 28 inches.

Page No. 740

Question 9. Identify Relationships The area of a swimming pool is 120 square meters. The width of the pool is 8 meters. What is the length of the pool in centimeters? length = _____ centimeters

Answer: Given that the area of a swimming pool is 120 square meters. The width of the pool is 8 meters. We have to find the length of the pool in centimeters. We know that Area of the rectangle = l × w A = l × w 120 square meters = l × 8 meters l × 8 meters = 120 square meters l = 120/8 = 15 meters Therefore, the length of the pool = 15 meters Convert meters to centimeters 1 meter = 100 centimeters 15 meters = 1500 centimeters. The length of the pool in centimeters = 1500 centimeters

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 68

Answer: An outdoor deck is 7 feet wide. The perimeter of the deck is 64 feet. We know that, P=(2 × l) + (2 × w) 64 feet = (2 × l) + (2 × 7) 64 feet = 2l + 14 feet 2 × l = 64 feet – 14 feet 2 × l = 50 feet l = 50/2 = 25 feet Therefore the length of the deck = 25 feet.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 69

Answer: A male mountain lion has a rectangular territory with an area of 96 square miles. Width = 8 miles Length =? A = l × w 96 square miles = l × 8 miles l × 8 miles = 96 square miles l = 96/8 l = 12 miles Therefore, length of his territory = 12 miles

Common Core – New – Page No. 741

Find Unknown Measures

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 70

Answer: length = 12 meters

Given, Perimeter = 42 meters Width = 9 meters P = (2 × l) + (2 × w) P = (2 × l) + (2 × 9 m) 42 m = 2l + 18 m 42 m – 18 m = 2l 2l = 24 meters l = 24 meters/2 = 12 meters Therefore length = 12 meters

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 72

Answer: height = 7 centimeters

Given, Area = 28 square centimeters Base = 4 cm A = b × h 28 square centimeters = 4 cm × h 4 × h = 28 h = 28/4 = 7 cm The height of the rectangle = 7 centimeters

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 73

Answer: base = 8 inches

Given, Area = 200 square inches Height = 25 inches Base = ? Area of the rectangle = b × h 200 square inches = b × 25 inches b × 25 inches = 200 square inches b = 200/25 = 8 inches The base of the rectangle = 8 inches.

Question 5. Susie is an organic vegetable grower. The perimeter of her rectangular vegetable garden is 72 yards. The width of the vegetable garden is 9 yards. How long is the vegetable garden? length = _____ yards

Answer: 27 yards

Susie is an organic vegetable grower. The perimeter of her rectangular vegetable garden is 72 yards. The width of the vegetable garden is 9 yards. P = 72 yards W = 9 yards L =? We know that, P = (2 × l) + (2 × w) 72 yards = (2 × l) + (2 × 9) 72 yards – 18 yards = (2 × l) (2 × l) = 72 yards – 18 yards 2l = 54 yards l = 54/2 = 27 yards Thus the vegetable garden is 27 yards long.

Question 6. An artist is creating a rectangular mural for the Northfield Community Center. The mural is 7 feet tall and has an area of 84 square feet. What is the length of the mural? length = _____ feet

An artist is creating a rectangular mural for the Northfield Community Center. The mural is 7 feet tall and has an area of 84 square feet. A = 84 square feet W = 7 feet L =? A = l × w 84 square feet = l × 7 feet l × 7 feet = 84 square feet l = 84/7 = 12 feet Thus the length of Murali is 12 feet.

Common Core – New – Page No. 742

Question 1. The area of a rectangular photograph is 35 square inches. If the width of the photo is 5 inches, how tall is the photo? Options: a. 5 inches b. 7 inches c. 25 inches d. 30 inches

Answer: 7 inches

The area of a rectangular photograph is 35 square inches. Width = 5 inches A = l × w 35 square inches = l × 5 inches Length = 35/5 = inches Thus the photo is 7 inches tall. The correct answer is option B.

Question 2. Natalie used 112 inches of blue yarn as a border around her rectangular bulletin board. If the bulletin board is 36 inches wide, how long is it? Options: a. 20 inches b. 38 inches c. 40 inches d. 76 inches

Answer: 20 inches

Natalie used 112 inches of blue yarn as a border around her rectangular bulletin board. Width = 36 inches A = 112 inches A = l × w 112 inches = l × 36 inches l × 36 inches = 112 inches l = 112/36 = 20 inches Length = 20 inches The correct answer is option A.

Question 3. A professional basketball court is in the shape of a rectangle. It is 50 feet wide and 94 feet long. A player ran one time around the edge of the court. How far did the player run? Options: a. 144 feet b. 194 feet c. 238 feet d. 288 feet

Answer: 288 feet

A professional basketball court is in the shape of a rectangle. It is 50 feet wide and 94 feet long. A player ran one time around the edge of the court. P = (2 × l) + (2 × w) P = (2 × 94 feet) + (2 × 50 feet) P = 188 feet + 100 feet = 288 feet Therefore the perimeter of the rectangle is 288 feet.

Question 4. On a compass, due east is a \(\frac{1}{4}\) turn clockwise from due north. How many degrees are in a \(\frac{1}{4}\) turn? Options: a. 45° b. 60° c. 90° d. 180°

On a compass, due east is a \(\frac{1}{4}\) turn clockwise from due north. \(\frac{1}{4}\) × 360° = 360°/4 = 90° The correct answer is option C.

Question 5. Hakeem’s frog made three quick jumps. The first was 1 meter. The second jump was 85 centimeters. The third jump was 400 millimeters. What was the total length of the frog’s three jumps? Options: a. 189 centimeters b. 225 centimeters c. 486 centimeters d. 585 millimeters

Answer: 225 centimeters

Hakeem’s frog made three quick jumps. The first was 1 meter. The second jump was 85 centimeters. The third jump was 400 millimeters. Convert other units to centimeters 1 meter = 100 centimeters 400 millimeters = 40 centimeters 100 + 85 + 40 = 225 centimeters Thus the correct answer is option B.

Question 6. Karen colors in squares on a grid. She colored \(\frac{1}{8}\) of the squares blue and \(\frac{5}{8}\) of the squares red. What fraction of the squares are not colored in? Options: a. \(\frac{1}{8}\) b. \(\frac{1}{4}\) c. \(\frac{1}{2}\) d. \(\frac{3}{4}\)

Answer: \(\frac{1}{4}\)

Karen colors in squares on a grid. She colored \(\frac{1}{8}\) of the squares blue and \(\frac{5}{8}\) of the squares red. \(\frac{1}{8}\) + \(\frac{5}{8}\) = \(\frac{6}{8}\) Total number of fractions = \(\frac{8}{8}\) \(\frac{8}{8}\) – \(\frac{6}{8}\) = \(\frac{2}{8}\) \(\frac{1}{4}\) fraction of the squares are not colored.

Page No. 745

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 74

Answer: Base = 12 feet Height = 8 feet A = b × h A wall = 12 feet × 8 feet A wall = 96 square feet

Question 1. Next, find the area of the door. A = b × h A door = _____ square feet

Answer: Base = 3 feet Height = 7 feet A = b × h A door = 3 feet × 7 feet A door = 21 square feet

Question 1. Last, subtract the area of the door from the area of the wall. _____ – _____ = _____ square feet So, Lila needs to cover _____ of wall. Type below: ________

Answer: A door = 21 square feet A wall = 96 square feet Last, subtract the area of the door from the area of the wall. A = A wall – A door A = 96 square feet – 21 square feet A = 75 square feet So, Lila needs to cover 75 square feet

Question 2. What if there was a square window on the wall with a side length of 2 feet? How much wall would Lila need to cover then? Explain. ______ square feet

Answer: If there is a square window of length 2 feet Area of square = s × s A window = 2 × 2 = 4 square feet Now Subtract the area of the door, area of the window from the area of the wall. A = 96 square feet – 21 square feet – 4 square feet A = 71 square feet Therefore Lila need to cover 71 square feet.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 75

Answer: Roof: Base = 20 inches Height = 30 inches Area of the roof = b × h A roof = 20 inches × 30 inches A roof = 600 inches Chimney: Base = 3 inches Height = 4 inches Area of the chimney = b × h A chimney = 3 × 4 = 12 inches Now subtract Area of Chimney from Area of the roof A = 600 inches – 12 inches A = 588 inches Therefore Ed needs 588 tiles.

Page No. 746

Question 4. Make Sense of Problems Lia has a dog and a cat. Together, the pets weigh 28 pounds. The dog weighs 3 times as much as the cat. How much does each pet weigh? cat weight = _____  pounds dog weight = _____ pounds

Answer: Given that, the pets weigh 28 pounds. 28 = 7 + 7 + 7 + 7 The dog weighs 3 times as much as the cat. = 3 × 7 = 21 pounds The dog weighs 21 pounds 28 – 21 = 7 The cat weighs = 7 pounds.

Question 5. Mr. Foster is covering two rectangular pictures with glass. One is 6 inches by 4 inches and the other one is 5 inches by 5 inches. Does he need the same number of square inches of glass for each picture? Explain. _____

Explanation: Mr. Foster is covering two rectangular pictures with glass. One is 6 inches by 4 inches and the other one is 5 inches by 5 inches. Area of first rectangular picture = 6 × 4 = 24 square inches Area of second rectangular picture = 5 × 5 = 25 square inches Area of two rectangular pictures = 25 square inches – 24 square inches 1 square inch. Therefore, he doesn’t need the same number of square inches of glass for each picture.

Question 6. Claire says the area of a square with a side length of 100 centimeters is greater than the area of a square with a side length of 1 meter. Is she correct? Explain. _____

Explanation: Claire says the area of a square with a side length of 100 centimeters is greater than the area of a square with a side length of 1 meter. Her statement is not correct because 1 meter = 100 centimeters. So, the area of a square with a side length of 100 centimeters is equal to the area of a square with a side length of 1 meter.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 76

Answer: Length = 12 feet Width = 11 feet Area of the rectangular floor = l × w = 12 feet × 11 feet = 132 square feet Room: Length = 9 feet Width = 7 feet Area of the floor in the room = l × w = 9 feet × 7 feet = 63 square feet Subtract the area of the rug from the area of the floor = 132 square feet – 63 square feet = 69 square feet The number of square feet of the floor that is NOT covered by the rug is 69 square feet.

Common Core – New – Page No. 747

Problem Solving Find the Area

Solve each problem.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 79

Explanation: Wall: Base = 14 feet Height = 8 feet Area of the wall = b × h A = 14 feet × 8 feet A = 112 square feet Window: Length = 4 feet Area of the square = s × s Area of the window = 4 feet × 4 feet = 16 square feet Now subtract Area of the window from the area of the rectangular wall = 112 square feet – 16 square feet = 96 square feet Therefore the area of the wall NOT including the window = 96 square feet.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area Common Core - New img 81

Answer: 235 square yards

Flower Garden: Base = 20 yards Height = 14 yards Area of the rectangular flower garden = b × h A = 20 yards × 14 yards A = 280 square yards Sod: Base = 5 yards Height = 9 yards Area of sod = b × h = 5 yards × 9 yards = 45 square yards Now subtract area of sod from area of flower garden = 280 square yards – 45 square yards = 235 square yards Thus the area covered with new sod = 235 square yards

Question 4. A rectangular painting is 24 inches wide and 20 inches tall without the frame. With the frame, it is 28 inches wide and 24 inches tall. What is the area of the frame not covered by the painting? The area of the frame = _____ square inches

Answer: 192 square inches

Explanation: A rectangular painting is 24 inches wide and 20 inches tall without the frame. A = b × h A = 24 inches × 20 inches A = 480 square inches With the frame, it is 28 inches wide and 24 inches tall. A = b × h A = 28 inches × 24 inches A = 672 square inches The area of the frame not covered by the painting = 672 square inches – 480 square inches = 192 square inches Therefore, The area of the frame = 192 square inches

Question 5. One wall in Jeanne’s bedroom is 13 feet long and 8 feet tall. There is a door 3 feet wide and 6 feet tall. She has a poster on the wall that is 2 feet wide and 3 feet tall. How much of the wall is visible? The area of the wall visible = _____ square feet

Answer: 80 square feet

Explanation: One wall in Jeanne’s bedroom is 13 feet long and 8 feet tall. Area of Jeanne’s bedroom = 13 feet × 8 feet = 104 square feet Area of door = 3 feet × 6 feet = 18 square feet Area of the wall = 2 feet × 3 feet = 6 square feet To find the area of the wall visible we have to subtract Area of the wall, Area of the door from Area of Jeanne’s bedroom. 104 square feet – 18 square feet – 6 square feet = 80 square feet The area of the wall visible = 80 square feet

Common Core – New – Page No. 748

Question 1. One wall in Zoe’s bedroom is 5 feet wide and 8 feet tall. Zoe puts up a poster of her favorite athlete. The poster is 2 feet wide and 3 feet tall. How much of the wall is not covered by the poster? Options: a. 16 square feet b. 34 square feet c. 35 square feet d. 46 square feet

Answer: 34 square feet

Explanation: One wall in Zoe’s bedroom is 5 feet wide and 8 feet tall. Area of the wall in Zoe’s bedroom = b × h A = 5 feet × 8 feet A = 40 square feet Zoe puts up a poster of her favorite athlete. The poster is 2 feet wide and 3 feet tall. Area of the poster = b × h A = 2 feet × 3 feet = 6 square feet Now subtract Area of the poster from the Area of the wall in Zoe’s bedroom = 40 square feet – 6 square feet = 34 square feet Thus the area of the wall is not covered by the poster = 34 square feet. The correct answer is option B.

Question 2. A garage door is 15 feet wide and 6 feet high. It is painted white, except for a rectangular panel 1 foot high and 9 feet wide that is brown. How much of the garage door is white? Options: a. 22 square feet b. 70 square feet c. 80 square feet d. 81 square feet

Answer: 81 square feet

Explanation: A garage door is 15 feet wide and 6 feet high. Area of the garage door = b × h A = 15 feet × 6 feet A = 90 square feet It is painted white, except for a rectangular panel 1 foot high and 9 feet wide that is brown. b = 9 feet h = 1 foot A = b × h A = 9 feet × 1 feet A = 9 square feet Area of the garage door is white = 90 square feet – 9 square feet Area of the garage door is white = 81 square feet The correct answer is option D.

Question 3. Kate baked a rectangular cake for a party. She used 42 inches of frosting around the edges of the cake. If the cake was 9 inches wide, how long was the cake? Options: a. 5 inches b. 12 inches c. 24 inches d. 33 inches

Explanation: Kate baked a rectangular cake for a party. She used 42 inches of frosting around the edges of the cake. Width = 9 inches P = (2 × l) + (2 × w) 42 inches = (2 × l) + (2 × 9) (2 × l) + (2 × 9) = 42 inches (2 × l) = 42 inches – 18 inches 2l = 24 inches l = 24/2 = 12 inches Therefore the cake is 12 inches long. Thus the correct answer is option B.

Question 4. Larry, Mary, and Terry each had a full glass of juice. Larry drank \(\frac{3}{4}\) of his. Mary drank \(\frac{3}{8}\) of hers. Terry drank \(\frac{7}{10}\) of his. Who drank less than \(\frac{1}{2}\) of their juice? Options: a. Larry b. Mary c. Mary and Terry d. Larry and Terry

Answer: Mary

Explanation: Larry, Mary, and Terry each had a full glass of juice. Larry drank \(\frac{3}{4}\), Mary drank \(\frac{3}{8}\) and Terry drank \(\frac{7}{10}\) of \(\frac{1}{2}\) \(\frac{3}{8}\) is less than \(\frac{1}{2}\) of their juice. The correct answer is Option B.

Question 5. Which of the following statements is NOT true about the numbers 7 and 9? Options: a. 7 is a prime number. b. 9 is a composite number. c. 7 and 9 have no common factors other than 1. d. 27 is a common multiple of 7 and 9.

Answer: 27 is a common multiple of 7 and 9

Explanation: a. 7 is a prime number is true. b. 9 is a composite number is true c. 7 and 9 have no common factors other than 1 is true. d. 27 is a common multiple of 7 and 9 is not true because 7 is not the multiple of 27. Thus the correct answer is option D.

Question 6. Tom and some friends went to a movie. The show started at 2:30 P.M. and ended at 4:15 P.M. How long did the movie last? Options: a. 1 hour 35 minutes b. 1 hour 45 minutes c. 1 hour 55 minutes d. 2 hours 15 minutes

Answer: 1 hour 45 minutes

Explanation: Tom and some friends went to a movie. The show started at 2:30 P.M. and ended at 4:15 P.M. Subtract 2:30 P.M. from 4:15 P.M. 4 hour 15 minutes -2 hour 30 minutes 1 hour 45 minutes The movie last for 1 hour 45 minutes Thus the correct answer is option B.

Page No. 749

Question 1. For numbers 1a–1e, select Yes or No to indicate if a rectangle with the given dimensions would have a perimeter of 50 inches. a. length: 25 inches; width: 2 inches i. yes ii. no

Explanation: P = (2 × l) + (2 × w) 50 inches = (2 × 25 in.) + (2 × w) (2 × w) = 50 inches – 50 inches w = 0 Thus the above statement is false

Question 1. b. length: 20 inches; width: 5 inches i. yes ii. no

Answer: Yes

Explanation: P = (2 × l) + (2 × w) 50 inches = (2 × 20 in.) + (2 × 5) 50 inches = 40 in. + 10 in. Thus the above statement is true.

Question 1. c. length: 17 inches; width: 8 inches i. yes ii. no

Explanation: P = (2 × l) + (2 × w) 50 inches = (2 × 17 in.) + (2 × 8 in.) 50 inches = 34 in. + 16 in. Thus the above statement is true.

Question 1. d. length: 15 inches; width: 5 inches i. yes ii. no

Explanation: P = (2 × l) + (2 × w) 50 inches = (2 × 15 in.) + (2 × 5 in.) 50 inches = 30 in. + 10 in. 50 inches = 40 inches Thus the above statement is false.

Question 1. e. length: 15 inches; width: 10 inches i. yes ii. no

Explanation: P = (2 × l) + (2 × w) 50 inches = (2 × 15 in.) + (2 × 10 in.) 50 inches = 30 in. + 20 in. 50 inches = 50 inches Thus the above statement is true.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 82

Answer: Pool: Base = 20 m Height = 16 m A = b × h Area of the pool = 20 m × 16 m = 320 square meters Pool and the walkway: Area of the pool and the walkway = 26 m × 22 m = 572 square meters

Question 2. Part B How many square meters of tile will Marco need for the walkway? Explain how you found your answer. A(walkway) = ____ m 2

Answer: 252 square meters

Explanation: Area of walkway = Area of the pool and the walkway – Area of pool Area of the walkway = 572 square meters – 320 square meters = 252 square meters Therefore the Area of walkway = 252 square meters

Page No. 750

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 83

Question 4. Kyleigh put a large rectangular sticker on her notebook. The height of the sticker measures 18 centimeters. The base is half as long as the height. What area of the notebook does the sticker cover? ________ square centimeters

Answer: 162 square centimeters

Explanation: Kyleigh put a large rectangular sticker on her notebook. The height of the sticker measures 18 centimeters. The base is half as long as the height. Base = h/2 = 18/2 = 9 centimeters Area of the rectangle = b × h A = 9 cm × 18 cm A = 162 square centimeters Thus the area of the notebook the sticker cover is 162 square centimeters.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 84

Answer: P = (2 × l) + (2 × w) 100 = (2 × l) + (2 × 20) 100 – 40 = 2 × l 2 × l = 60 l = 60/2 = 30 feet Length = 30 feet So, the length of the garden 30 feet.

Question 6. Gary drew a rectangle with a perimeter of 20 inches. Then he tried to draw a square with a perimeter of 20 inches. Draw 3 different rectangles that Gary could have drawn. Then draw the square, if possible. Type below: __________

Go Math Grade 4 Chapter 13 Answer Key review solution image-1

Page No. 751

Question 7. Ami and Bert are drawing plans for rectangular vegetable gardens. In Ami’s plan, the garden is 13 feet by 10 feet. In Bert’s plan, the garden is 12 feet by 12 feet. For numbers 7a−7d, select True or False for each statement. a. The area of Ami’s garden is 130 square feet. i. True ii. False

Answer: True

Explanation: A = b × h Area of Ami’s garden = 13 feet × 10 feet = Area of Ami’s garden = 130 square feet The above statement is true.

Question 7. b. The area of Bert’s garden is 48 square feet. i. True ii. False

Answer: False

Explanation: Area of Bert’s garden = 12 feet × 12 feet = 144 square feet The above statement is false.

Question 7. c. Ami’s garden has a greater area than Bert’s garden. i. True ii. False

Explanation: Area of Ami’s garden = 13 feet × 10 feet = 130 square feet Area of Bert’s garden = 12 feet × 12 feet = 144 square feet 130 square feet is less than 144 square feet The area of Ami’s garden is less than Area of Bert’s garden. The above statement is false.

Question 7. d. The area of Bert’s garden is 14 square feet greater than Ami’s. i. True ii. False

Explanation: Area of Ami’s garden = 13 feet × 10 feet = 130 square feet Area of Bert’s garden = 12 feet × 12 feet = 144 square feet 144 square feet – 130 square feet = 14 square feet The above statement is true.

Question 8. A farmer planted corn in a square field. One side of the field measures 32 yards. What is the area of the cornfield? Show your work. _______ square yards

Answer: 1024 square yards

Explanation: A farmer planted corn in a square field. One side of the field measures 32 yards. Area of the square = 32 yards × 32 yards A = 1,024 square yards Therefore the area of the cornfield is 1,024 square yards.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 85

Answer: 136 square inches

Explanation: Area of the picture = 12 in. × 18 in. A = 216 square inches Area of the frame = 16 in. × 22 in. A = 352 square inches The area of the frame not covered by the picture = 352 square inches – 216 square inches = 136 square inches Therefore the area of the frame not covered by the picture is 136 square inches.

Question 10. Kelly has 236 feet of fence to use to enclose a rectangular space for her dog. She wants the width to be 23 feet. Draw a rectangle that could be the space for Kelly’s dog. Label the length and width. Type below: ________

HMH Go Math Answer Key Grade 4 Chapter 13 review solution img- 5

Page No. 752

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 86

Answer: 1100 square yards

Explanation: Addition: Top: Base = 40 yards Height = 20 yards Area of the top rectangle = b × h A = 40 yards × 20 yards = 800 square yards Bottom: Base = 30 yards Height = 10 yards Area of the rectangle = b × h A = 30 yards × 10 yards = 300 square yards Area of the parking = Area of top + Area of bottom A = 800 square yards + 300 square yards Area of parking = 1100 square yards.

Question 12. Chad’s bedroom floor is 12 feet long and 10 feet wide. He has an area rug on his floor that is 7 feet long and 5 feet wide. Which statement tells how to find the amount of the floor that is not covered by the rug? Mark all that apply. Options: a. Add 12 × 10 and 7 × 5. b. Subtract 35 from 12 × 10 c. Subtract 10 × 5 from 12 × 7. d. Add 12 + 10 + 7 + 5. e. Subtract 7 × 5 from 12 × 10. f. Subtract 12 × 10 from 7 × 5.

Answer: B, F

Chad’s bedroom floor is 12 feet long and 10 feet wide. A = 12 feet × 10 feet = 120 square feet Area rug on his floor = 7 feet × 5 feet = 35 square feet To find the amount of the floor that is not covered by the rug we have to subtract 120 square feet from 35 square feet or 35 square feet from 12 × 10. So, the correct answers are B and F.

Question 13. A row of plaques covers 120 square feet of space along a wall. If the plaques are 3 feet tall, what length of the wall do they cover? ____ feet

Answer: 40 feet

Explanation: Given that, A row of plaques covers 120 square feet of space along a wall. Height = 3 feet A = b × h 120 square feet = b × 3 feet b = 120/3 = 40 Therefore the base is 40 feet.

Page No. 753

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 87

Answer: She can find the area of each rectangle and then find the sum. The area of the living room is 20 × 20 = 400 square feet. The area of the dining room is 15 × 10 = 150 square feet. The sum of the two rooms = 400 + 150 = 550 square feet. She needs 550 square feet of carpeting.

Question 15. Lorenzo built a rectangular brick patio. He is putting a stone border around the edge of the patio. The width of the patio is 12 feet. The length of the patio is two feet longer than the width. How many feet of stone will Lorenzo need? Explain how you found your answer. ____ feet

Answer: 52 feet

Explanation: Width = 12 feet Length = 2 × width Length = 2 + 12 feet = 14 feet Perimeter = (2 × l) + (2 × w) P = (2 × 14) + (2 × 12) P = 28 + 24 P = 52 feet

Page No. 754

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 88

Answer: A, C

Explanation: i. Perimeter of A = (2 × l) + (2 × w) P = (2 × 1) + (2 × 4) = 2 + 8 = 10 feet ii. Perimeter of B = (2 × l) + (2 × w) P = (2 × 2) + (2 × 5) = 4 + 10 = 14 feet iii. Perimeter of C = (2 × l) + (2 × w) P = (2 × 2) + (2 × 3) = 4 + 6 = 14 feet iv. Perimeter of D = (2 × l) + (2 × w) P = (2 × 4) + (2 × 6) = 8 + 12 = 20 feet The correct answer is option A and C.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 89

Answer: Subtract the area of the sticker from the area of the notebook.

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 90

Answer: a. 1 × 8 and 5 × 2 _______ Yes b. 3 × 5 and 1 × 8 _______ No c. 2 × 5 and 1 × 3 and 1 × 3 _______ No

Go Math Grade 4 Answer Key Chapter 13 Algebra Perimeter and Area img 91

Answer: 5 feet long by 3 feet wide Area of the rectangle = l × w A = 15 square feet The factor of 15 is 5 and 3. So, the length = 5 feet long Width = 3 feet long.

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Conclusion:

We wish you all have satisfied with the solutions exists in the Go Math Grade 4 Answer Key Chapter 13 Algebra: Perimeter and Area. For better practice sessions refer to the questions given at the end of the chapter and solve them properly with the help of topic-wise chapter 13 Go Math 4th Grade Answer Key. Practice all problems easily and score well in any standard tests or exams.

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Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures

Students who are willing to practice more number of questions can Download Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures pdf. Here we provide the solutions for each and every question with pictures in an easy manner. With the help of Go Math Grade 4 Homework Practice FL Chapter 10 Answer Key, you can complete your homework in time.

The topics of Two-Dimensional Figures consist of Lines, Rays and Angles, Classify Triangles, Parallel Lines and Perpendicular Lines, Classify Quadrilaterals, Line Symmetry, and so on. All you have to do is to click on the below links and kickstart your preparation.

Lesson: 1 – Lines, Rays, and Angles

Common Core – Two-Dimensional Figures – Page No. 189

Common core – two-dimensional figures – page no. 190.

Lesson: 2 – Classify Triangles

Common Core – Two-Dimensional Figures – Page No. 191

Common core – two-dimensional figures – page no. 192.

Lesson: 3 – Parallel Lines and Perpendicular Lines

Common Core – Two-Dimensional Figures – Page No. 193

Common core – two-dimensional figures – page no. 194.

Lesson: 4 – Classify Quadrilaterals

Common Core – Two-Dimensional Figures – Page No. 195

Common core – two-dimensional figures – page no. 196.

Lesson: 5 – Line Symmetry

Common Core – Two-Dimensional Figures – Page No. 197

Common core – two-dimensional figures – page no. 198.

Lesson: 6 – Find and Draw Lines of Symmetry

Common Core – Two-Dimensional Figures – Page No. 199

Common core – two-dimensional figures – page no. 200.

Lesson: 7 – Problem Solving Shape Patterns

Common Core – Two-Dimensional Figures – Page No. 201

Common core – two-dimensional figures – page no. 202.

Chapter 10 – Extra Practice

Common Core – Two-Dimensional Figures – Page No. 203

Common core – two-dimensional figures – page no. 204.

Lines, Rays, and Angles

Draw and label an example of the figure.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 1

Explanation: An obtuse angle is greater than a right angle. The middle letter, B, names the vertex of the angle.

Question 2. \(\overrightarrow{G H}\)

grade 4 chapter 10 Lines, Rays, and Angles image 2 553

Explanation: GH is a ray that has one endpoint and continues without an end in one direction.

Question 3. acute ∠JKL ________

grade 4 chapter 10 Lines, Rays, and Angles image 3 553

Explanation: Angle JKL is an acute angle that is less than a right angle.

Question 4. \(\overline{B C}\)

grade 4 chapter 10 Lines, Rays, and Angles image 4 553

Explanation: BC is a line that continues without an end in both directions.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 2

Question 5. Name a line segment.

Answer: line segment EF

Explanation: EF line is a straight path of points that continues without an end in both directions.

Question 6. Name a right angle. ∠ _____

Answer: ∠EJF

Explanation: EJF is a right angle that forms a square corner.

Question 7. Name an obtuse angle. obtuse ∠ _____

Answer: ∠CEJ

Explanation: CEJ is an obtuse angle that is greater than a right angle.

Problem Solving

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 3

Question 9. Classify ∠AFD ________

Answer: Obtuse Angle

Explanation: AFD is an obtuse angle that is greater than a right angle.

Question 10. Classify ∠CFE. ________

Answer: Right Angle

Explanation: ∠CFE is a right angle that forms a square corner.

Question 11. Name two acute angles. acute ∠ _____ acute ∠ _____

Answer: ∠AFB and ∠DFE

Explanation: ∠AFB and ∠DFE are two acute angles with less than a right angle.

Lesson Check

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 4

Answer: c. obtuse

Explanation: The hands of the time 12:25 are forming greater than a right angle. So, the answer is the Obtuse angle. Thus the correct answer is option c.

Question 2. Which of the following name two different figures? Options: a. \(\overline{A B} \text { and } \overline{B A}\) b. \(\overleftrightarrow { AB } \) and \(\overleftrightarrow { BA } \) c. \(\overrightarrow { AB } \) and \(\overrightarrow { BA } \) d. ∠ABC and ∠CBA

Answer: \(\overrightarrow { AB } \) and \(\overrightarrow { BA } \)

Explanation: In \(\overrightarrow { AB } \) A is an end point and B continues without end in one direction. In \(\overrightarrow { BA } \) B is an end point and A continues without an end in one direction. Thus the correct answer is option c.

Spiral Review

Question 3. Jan’s pencil is 8.5 cm long. Ted’s pencil is longer. Which could be the length of Ted’s pencil? Options: a. 0.09 cm b. 0.8 cm c. 8.4 cm d. 9.0 cm

Answer: d. 9.0 cm

Explanation: 9 ones is greater than 8 ones. So, 9.0 cm > 8.5 cm Thus the correct answer is option d.

Question 4. Kayla buys a shirt for $8.19. She pays with a $10 bill. How much change should she receive? Options: a. $1.81 b. $1.89 c. $2.19 d. $2.81

Answer: a. $1.81

Explanation: Kayla buys a shirt for $8.19. She pays with a $10 bill. To find the change she received, $10 – $8.19 = 1.81 Thus the correct answer is option a.

Question 5. Sasha donated \(\frac{9}{100}\) of her class’s entire can collection for the food drive. Which decimal is equivalent to \(\frac{9}{100}\) ? Options: a. 9 b. 0.99 c. 0.9 d. 0.09

Answer: d. 0.09

Explanation: \(\frac{9}{100}\) is 9 hundredths. So, the decimal is 0.09. Thus the correct answer is option d.

Question 6. Jose jumped 8 \(\frac{1}{3}\) feet. This was 2 \(\frac{2}{3}\) feet farther than Lila jumped. How far did Lila jump? Options: a. 5 \(\frac{1}{3}\) b. 5 \(\frac{2}{3}\) c. 6 \(\frac{1}{3}\) d. 11

Answer: 5 \(\frac{2}{3}\)

Explanation: Jose jumped 8 \(\frac{1}{3}\) feet. This was 2 \(\frac{2}{3}\) feet farther than Lila jumped. 8 \(\frac{1}{3}\) feet – 2 \(\frac{2}{3}\) = 25/3 – 8/3 = 7/3 = 5 \(\frac{2}{3}\) Thus the correct answer is option b.

Classify Triangles

Classify each triangle. Write acute, right, or obtuse.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 5

Answer: Obtuse triangle; Angle A and Angle C are both acute. Angle B is obtuse.

Explanation: From triangle, ABC, Angle A, and Angle C are both acute with less than a right angle. Angle B is an obtuse angle that is greater than a right angle.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 6

Answer: Right Triangle; Triangle DEF; ∠D and ∠F are acute angles. ∠E is Right angle

Explanation: ∠D and ∠F are acute angles with less than a right angle. ∠E is the Right angle that forms a square corner. A triangle that has one right angle is called a right triangle.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 7

Answer: Acute triangle; Angle G, Angle J, and Angle H are acute angles.

Explanation: From triangle GJH, Angle G, Angle J, and Angle H are acute angles with less than a right angle. A triangle with three acute angles called an acute triangle. So, the given triangle is an acute triangle.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 8

Answer: Obtuse triangle; Angle L and Angle N are both acute. Angle M is obtuse.

Explanation: From triangle LMN, Angle L and Angle N are both acute with less than a right angle. Angle M is an obtuse angle that is greater than a right angle. A triangle with an obtuse angle is called an obtuse triangle.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 9

Two Acute triangles. △ ABD △ BCD

Explanation: If we draw a line segment from point B to point D, then there are two traingles formed with less than right angles. They are △ ABD and △ BCD.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 10

Two Acute triangles. △ ABC △ ADC

Explanation: If we draw a line segment from point A to point C, then there are two triangles formed with less than right angles. They are △ ABC and △ ADC.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 11

Answer: a. 0

Explanation: The given image has three acute angles. So, there are 0 obtuse angles. Thus the correct answer is option a.

Question 2. Joan was asked to draw a right triangle. How many right angles are in a right triangle? Options: a. 0 b. 1 c. 2 d. 3

Answer: b. 1

Explanation: A right triangle has only one right angle. Thus the correct answer is option b.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 12

Answer: b. ray SE

Explanation: SE is a ray that has one endpoint and continues without an end in one direction. Thus the correct answer is option b.

Question 4. Armon added \(\frac{1}{10}\) and \(\frac{8}{100}\). Which is the correct sum? Options: a. \(\frac{18}{10}\) b. \(\frac{9}{10}\) c. \(\frac{9}{100}\) d. \(\frac{18}{100}\)

Answer: d. \(\frac{18}{100}\)

Explanation: \(\frac{10}{100}\) + \(\frac{8}{100}\) = \(\frac{18}{100}\) Thus the correct answer is option d.

Question 5. Sam counted out loud by 6s. Jorge counted out loud by 8s. What are the first three numbers both students said? Options: a. 8, 16, 24 b. 14, 28, 42 c. 24, 48, 72 d. 48, 96, 144

Answer: c. 24, 48, 72

Explanation: Sam counted out loud by 6s = 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72. Jorge counted out loud by 8s = 8, 16, 24, 32, 40, 48, 56, 64, 72, 80. Both students said the first three numbers are 24, 48, 72. Thus the correct answer is option c.

Question 6. A basketball team averaged 105 points per game. How many points did the team score in 6 games? Options: a. 605 points b. 630 points c. 900 points d. 6,030 points

Answer: b. 630 points

Explanation: A basketball team averaged 105 points per game. They score in 6 games = 6 x 105 = 630 points. Thus the correct answer is option b.

Parallel Lines and Perpendicular Lines

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 13

Question 1. Name a pair of lines that appear to be perpendicular. Think: Perpendicular lines form right angles. \(\overleftrightarrow { AB } \) and \(\overleftrightarrow { EF } \) appear to form right angles. \(\overleftrightarrow { AB } \) and \(\overleftrightarrow { EF } \)

Answer: \(\overleftrightarrow { AB } \) and \(\overleftrightarrow { EF } \)

Explanation: Perpendicular lines form right angles. \(\overleftrightarrow { AB } \) and \(\overleftrightarrow { EF } \) appear to form right angles. \(\overleftrightarrow { AB } \) and \(\overleftrightarrow { EF } \)

Question 2. Name a pair of lines that appear to be parallel. ____ and ____

Answer: \(\overleftrightarrow { AB } \) and \(\overleftrightarrow { CD } \)

Explanation: Parallel lines never interest each other. \(\overleftrightarrow { AB } \) and \(\overleftrightarrow { CD } \) are parallel lines.

Question 3. Name another pair of lines that appear to be perpendicular. ____ and ____

Answer: \(\overleftrightarrow { CD } \) and \(\overleftrightarrow { EF } \)

Explanation: Perpendicular lines form right angles. \(\overleftrightarrow { CD } \) and \(\overleftrightarrow { EF } \) appear to form right angles. \(\overleftrightarrow { CD } \) and \(\overleftrightarrow { EF } \)

Draw and label the figure described.

Question 4. \(\overleftrightarrow { MN } \) and \(\overleftrightarrow { PQ } \) intersecting at point R

grade 4 chapter 10 Lines, Rays, and Angles image 1 565

Explanation: MN and PQ are two lines and interesting at point R.

Question 5. \(\overleftrightarrow { WX } \) || \(\overleftrightarrow { YZ } \)

grade 4 chapter 10 Lines, Rays, and Angles image 2 565

Explanation: WX and YZ are parallel lines and they never intersect with each other.

Question 6. \(\overleftrightarrow { FH } \) ⊥ \(\overleftrightarrow { JK } \)

grade 4 chapter 10 Lines, Rays, and Angles image 3 565

Explanation: FH and JK are two lines and intersecting each other to form four right angles.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 14

Question 7. Name two streets that intersect but do not appear to be perpendicular. Type below: _______

Answer: Maple and Oak or Oak and Birch

Explanation: Maple and Oak or Oak and Birch; They are intersecting with each other and not perpendicular.

Question 8. Name two streets that appear to be parallel to each other. Type below: _______

Answer: Maple and Birch

Explanation: Maple and Birch are streets and not intersect with each other. They appear to be parallel to each other.

Question 1. Which capital letter appears to have perpendicular line segments? Options: a. N b. O c. T d. V

Answer: c. T

Explanation: T has two lines and interesting to form four right angles.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 15

Answer: c. \(\overline{F G} \text { and } \overline{J H}\)

Explanation: \(\overline{F G} \text { and } \overline{J H}\) are parallel lines that never intersect

Question 3. Nolan drew a right triangle. How many acute angles did he draw? Options: a. 0 b. 1 c. 2 d. 3

Answer: c. 2

Explanation: A triangle with one right angle will have two acute angles.

Question 4. Mike drank more than half the juice in his glass. What fraction of the juice could Mike have drunk? Options: a. \(\frac{1}{3}\) b. \(\frac{2}{5}\) c. \(\frac{3}{6}\) d. \(\frac{5}{8}\)

Answer: d. \(\frac{5}{8}\)

Explanation: Mike drank more than half the juice in his glass. He drunk \(\frac{5}{8}\) of the juice.

Question 5. A school principal ordered 1,000 pencils. He gave an equal number to each of 7 teachers until he had given out as many as possible. How many pencils were left? Options: a. 2 b. 4 c. 6 d. 142

Answer: c. 6

Explanation: A school principal ordered 1,000 pencils. He gave an equal number to each of the 7 teachers until he had given out as many as possible. He shared 142 pencils for each of the 7 teachers. So, 142 × 7 = 994. The remaining pencils are 6.

Question 6. A carton of juice contains 64 ounces. Ms. Wilson bought 6 cartons of juice. How many ounces of juice did she buy? Options: a. 364 ounces b. 370 ounces c. 384 ounces d. 402 ounces

Answer: c. 384 ounces

Explanation: A carton of juice contains 64 ounces. Ms. Wilson bought 6 cartons of juice. 64 X 6 = 384 ounces juice she can buy.

Classify Quadrilaterals

Classify each figure as many ways as possible. Write quadrilateral, trapezoid, parallelogram, rhombus, rectangle, or square.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 16

Explanation: 2 pairs of parallel sides 4 sides of equal length 0 right angles Quadrilateral, Parallelogram, and rhombus.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 17

Answer: Quadrilateral, Parallelogram, Rectangle

Explanation: 2 pairs of parallel sides 2 pairs of sides of equal length 4 right angles Quadrilateral, Parallelogram, Rectangle

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 18

Explanation: 1 pair of parallel sides 2 sides of equal length 0 right angles Quadrilateral, Trapezoid

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 19

Answer: Quadrilateral

Explanation: 0 pair of parallel sides 0 sides of equal length 0 right angles Quadrilateral

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 20

Answer: Quadrilateral, Parallelogram, and rhombus

Explanation: 2 pairs of parallel sides 4 sides of equal length 0 right angles Quadrilateral, Parallelogram, and rhombus

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 21

Explanation: 1 pair of parallel sides 0 sides of equal length 2 right angles Quadrilateral, Trapezoid

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 22

Explanation: 2 pairs of parallel sides 2 pairs of sides of equal length 0 right angles Quadrilateral, Parallelogram

Question 8. Alan drew a polygon with four sides and four angles. All four sides are equal. None of the angles are right angles. What figure did Alan draw? ________

Answer: Quadrilateral or rhombus

Explanation: Alan drew a polygon with four sides and four angles. All four sides are equal. None of the angles are right angles. Alan drew Quadrilateral or rhombus

Question 9. Teresa drew a quadrilateral with 2 pairs of parallel sides and 4 right angles. What quadrilateral could she have drawn? ________

Answer: square or rectangle

Explanation: 2 pairs of parallel sides and 4 right angles. she could draw a square or rectangle.

Question 1. Joey is asked to name a quadrilateral that is also a rhombus. What should be his answer? Options: a. square b. rectangle c. parallelogram d. trapezoid

Answer: a. square

Explanation: The quadrilateral square is also called a rhombus. Both square and rhombus have 2 pairs of parallel sides and 4 sides of equal length. Thus the correct answer is option a.

Question 2. Which quadrilateral has exactly one pair of parallel sides? Options: a. square b. rhombus c. parallelogram d. trapezoid

Answer: d. trapezoid

Explanation: A trapezoid has exactly one pair of parallel sides. Thus the correct answer is option d.

Question 3. Terrence has 24 eggs to divide into equal groups. What are all the possible numbers of eggs that Terence could put in each group? Options: a. 1, 2, 3, 4 b. 2, 4, 6, 8, 12 c. 1, 2, 3, 4, 6, 8, 12, 24 d. 24, 48, 72, 96

Answer: c. 1, 2, 3, 4, 6, 8, 12, 24

Explanation: Terrence has 24 eggs to divide into equal groups. Terence could put in each group in 1, 2, 3, 4, 6, 8, 12, 24 ways. Thus the correct answer is option c.

Question 4. In a line of students, Jenna is number 8. The teacher says that a rule for a number pattern is add 4. The first student in line says the first term, 7. What number should Jenna say? Options: a. 31 b. 35 c. 39 d. 43

Answer: b. 35

Explanation: In a line of students, Jenna is number 8. The teacher says that a rule for a number pattern is to add 4. The first student in line says the first term, 7. 7 + 4 = 11 11 + 4 = 15 15 + 4 = 19 19 + 4 = 23 23 + 4 = 27 27 + 4 = 31 31 + 4 = 35. Jenna says 35. Thus the correct answer is option b.

Question 5. Lou eats \(\frac{6}{8}\) of a pizza. What fraction of the pizza is left over? Options: a. \(\frac{1}{8}\) b. \(\frac{1}{4}\) c. \(\frac{1}{2}\) d. \(\frac{3}{4}\)

Answer: b. 1/4 Explanation: Lou eats 6/8 of a pizza. So, 6 parts of the pizza are finished and the remaining 2 parts of the pizza have remained. So, the left over pizza is 2/8 = 1/4. Thus the correct answer is option b.

Question 6. Which capital letter appears to have parallel lines? Options: a. D b. L c. N d. T

Answer: c. N

Explanation: N has two parallel lines and never intersect each other. Thus the correct answer is option c.

Line Symmetry

Tell if the dashed line appears to be a line of symmetry. Write yes or no.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 23

Answer: Yes

Explanation: The line of symmetry divides a shape into two parts that are the same size and shape.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 24

Explanation: The line of symmetry divides a shape into two parts that are not of the same size and shape.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 25

Complete the design by reflecting over the line of symmetry.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 31

Answer: a. horizontal

Explanation: The horizontal line of symmetry in the letter D can exactly separate two parts equally.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 35

Question 3. The class has 360 unit cubes in a bag. Johnnie divides the unit cubes equally among 8 groups. How many unit cubes will each group get? Options: a. 40 b. 44 c. 45 d. 48

Answer: c. 45

Explanation: The class has 360 unit cubes in a bag. Johnnie divides the unit cubes equally among 8 groups. 360/8= 45.

Question 4. There are 5,280 feet in one mile. How many feet are there in 6 miles? Options: a. 30,680 b. 31,260 c. 31,608 d. 31,680

Answer: d. 31,680

Explanation: There are 5,280 feet in one mile. So, for 6 miles = 6 x 5, 280 = 31,680.

Question 5. Sue has 4 pieces of wood. The lengths of her pieces of wood are \(\frac{1}{3}\) foot, \(\frac{2}{5}\) foot, \(\frac{3}{10}\) foot, and \(\frac{1}{4}\) foot. Which piece of wood is the shortest? Options: a. the \(\frac{1}{3}\) foot piece b. the \(\frac{2}{5}\) foot piece c. the \(\frac{3}{10}\) foot piece d. the \(\frac{1}{4}\) foot piece

Answer: d. the 1/4 foot piece

Explanation: The lengths of 1/4 foot piece is less compared to other lengths.

Question 6. Alice has \(\frac{1}{5}\) as many miniature cars as Sylvester has. Sylvester has 35 miniature cars. How many miniature cars does Alice have? Options: a. 7 b. 9 c. 40 d. 175

Answer: a. 7

Explanation: Alice has 1/5 as many miniature cars as Sylvester has. Sylvester has 35 miniature cars. Alice has 1/5 × 35 = 7 miniature cars.

Find and Draw Lines of Symmetry

Tell whether the shape appears to have zero lines, 1 line, or more than 1 line of symmetry. Write zero, 1, or more than 1.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 39

Answer: more than 1

Explanation: There is more than 1 line of symmetry that separates two parts equally.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 40

Answer: Zero

Explanation: There are 0 lines of symmetries.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 42

Explanation:

grade 4 chapter 10 Lines, Rays, and Angles image 2 585

Does the design have line symmetry? Write yes or no. If your answer is yes, draw all lines of symmetry.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 43

Draw a shape for the statement. Draw the line or lines of symmetry.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 47

Question 12. Which number or numbers appear to have only 1 line of symmetry? ____

Explanation: The number 3 has only 1 line of symmetry.

Question 13. Which number or numbers appear to have 2 lines of symmetry? ____

Answer: 0 and 8

Explanation: The numbers 0 and 8 appear to have 2 lines of symmetry.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 51

The trapezoid has exactly 1 line of symmetry. Thus the correct answer is option d.

Question 3. Richard practiced each of 3 piano solos for \(\frac{5}{12}\) hour. How long did he practice in all? Options: a. \(\frac{2}{3}\) hours b. 1 \(\frac{1}{4}\) hours c. 1 \(\frac{1}{3}\) hours d. 1 \(\frac{5}{12}\) hours

Answer: b. 1 1/4 hours

Explanation: Richard practiced each of 3 piano solos for 5/12 hour. 5/12 hour = 1 1/4 hours hours. Thus the correct answer is option b.

Question 4. Which of the following decimals is equivalent to three and ten hundredths? Options: a. 0.30 b. 0.31 c. 3.01 d. 3.1

Answer: d. 3.1

Explanation: three and ten hundredths = 310 hundredths = 3.1 Thus the correct answer is option d.

Question 5. Lynne used \(\frac{3}{8}\) cup of flour and \(\frac{1}{3}\) cup of sugar in a recipe. Which number below is a common denominator for \(\frac{3}{8}\) and \(\frac{1}{3}\)? Options: a. 8 b. 12 c. 16 d. 24

Answer: d. 24

Explanation: Lynne used 3/8 cup of flour and 1/3 cup of sugar in a recipe. To find the common denominator for 3/8 and 1/3, multiply 8 X3 and 3 X 8 = 24. Thus the correct answer is option d.

Question 6. Kevin draws a figure that has four sides. All sides have the same length. His figure has no right angles. What figure does Kevin draw? Options: a. square b. trapezoid c. rhombus d. rectangle

Answer: c. rhombus

Problem Solving Shape Patterns

Solve each Problem.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 56

The pattern repeats one triangle followed by two squares.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 57

Add one more column with 1 more circle than in the previous column; 21.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 58

2 triangles placed side to side followed by 2 sets of 2 triangles placed vertex to vertex

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 59

Explanation: From the pattern, the missing image will have a vertical rectangle with the circle and X mark in it.

Question 3. Chad has two pieces of wood. One piece is \(\frac{7}{12}\) foot long. The second piece is \(\frac{5}{12}\) foot longer than the first piece. How long is the second piece? Options: a. \(\frac{2}{12}\) foot b. \(\frac{1}{2}\) foot c. \(\frac{12}{18}\) foot d. 1 foot

Answer: d. 1 foot

Explanation: 7/12 + 5/12 = 12/12 = 1 foot.

Question 4. Olivia finished a race in 40.64 seconds. Patty finished the race in 40.39 seconds. Miguel finished the race in 41.44 seconds. Chad finished the race in 40.46 seconds. Who finished the race in the least time? Options: a. Olivia b. Patty c. Miguel d. Chad

Answer: b. Patty

Explanation: Patty finished the race in 40.39 seconds that is the least time compared to others.

Question 5. Justin bought 6 ribbons for an art project. Each ribbon is \(\frac{1}{4}\) yard long. How many yards of ribbon did Justin buy? Options: a. \(\frac{2}{3}\) yard b. 1 \(\frac{1}{4}\) yards c. 1 \(\frac{1}{2}\) yards d. 1 \(\frac{3}{4}\) yards

Answer: c. 1 1/2 yards

Explanation: Justin bought 6 ribbons for an art project. Each ribbon is 1/4 yard long. So, 6 X 1/4 = 3/2 = 1 1/2 yards.

Question 6. Kyle and Andrea were asked to make a list of prime numbers. Kyle: 1, 3, 7, 19, 23 Andrea: 2, 3, 5, 7, 11 Whose list is correct? Options: a. Only Kyle’s list b. Only Andrea’s list c. Both lists are correct. d. Neither list is correct.

Answer: b. Only Andrea’s list

Explanation: 1 is not a prime number. So, the answer is Only Andrea’s list is correct.

Lesson 10.1

Question 1. acute ∠MNP Type below: _________

Question 2. \(\overline{Q R}\) Type below: _________

Question 3. \(\overrightarrow { TS } \) Type below: _________

Lesson 10.2

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 69

Answer: Acute

Explanation: The above triangle is less than 90º, thus the above figure is an acute angle triangle.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 70

Answer: Obtuse

Explanation: The above triangle is greater than 90º, thus the above figure is an obtuse angle triangle.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 71

Answer: Right

Explanation: The above figure has 90º, thus the above figure is an right angle triangle.

Lesson 10.3

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 72

Question 7. Name two streets that appear to be parallel. _________

Answer: Oak and elm

Explanation: By seeing the above figure we say that Oak and Elm are two non-intersecting lines. Thus the two streets that appear to be parallel are Oak and Elm.

Question 8. Name two streets that appear to be perpendicular. Type below: _________

Answer: Park and Oak or Park and Elm

Explanation: Park and Oak, Park and Elm are intersecting lines, thus the two streets that appear to be perpendicular are Park and Oak or Park and Elm.

Lesson 10.4

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 73

Answer: Quadrilateral, Trapezoid

Lesson 10.5

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 75

Explanation: The line of symmetry divides a shape into two parts that are the same size and shape.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 76

Lesson 10.6

Does the design have line symmetry? Write yes or no.

If your answer is yes, draw all lines of symmetry.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 78

Explanation: The line of symmetry divides a shape into two parts that are not with the same size and shape. The above figure is not symmetrical.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 79

The above figure is symmetrical.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 80

Explanation: The above figure is symmetrical.

Lesson 10.7

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 81

Answer: The pattern repeats circle, square, circle.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures Common Core - Two-Dimensional Figures img 82

Answer: The pattern grows by one triangle each time.

Conclusion:

Refer Go Math Grade 4 Answer Key Homework Practice FL Chapter 10 Two-Dimensional Figures to score the highest marks in the exam. Our aim to provide quick learning with clear-cut explanations for all the students of Grade 4. In addition to this students can also follow Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures to get an idea of the model of questions. All the very best!!!

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