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Case Study Questions for Class 8 Maths

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Case Study Questions for Class 8 Maths

Table of Contents

Here in this article, we are providing case study questions for class 8 maths.

Maths Class 8 Chapter List

Latest chapter list (2023-24).

Chapter 1 Rational Numbers Chapter 2 Linear Equations in One Variable Chapter 3 Understanding Quadrilaterals Chapter 4 Data Handling Chapter 5 Squares and Square Roots Chapter 6 Cubes and Cube Roots Chapter 7 Comparing Quantities Chapter 8 Algebraic Expressions and Identities Chapter 9 Mensuration Chapter 10 Exponents and Powers Chapter 11 Direct and Indirect proportions Chapter 12 Factorisation Chapter 13 Introduction to Graphs

Old Chapter List

Chapter 1 Rational Numbers Chapter 2 Linear Equations in One Variable Chapter 3 Understanding Quadrilaterals Chapter 4 Practical Geometry Chapter 5 Data Handling Chapter 6 Squares and Square Roots Chapter 7 Cubes and Cube Roots Chapter 8 Comparing Quantities Chapter 9 Algebraic Expressions and Identities Chapter 10 Visualising Solid Shapes Chapter 11 Mensuration Chapter 12 Exponents and Powers Chapter 13 Direct and Indirect proportions Chapter 14 Factorisation Chapter 15 Introduction to Graphs Chapter 16 Playing with Numbers

Tips for Answering Case Study Questions for Class 8 Maths in Exam

Case Study Questions for Class 8 Maths

1. Comprehensive Reading for Context: Prioritize a thorough understanding of the provided case study. Absorb the contextual details and data meticulously to establish a strong foundation for your solution.

2. Relevance Identification: Pinpoint pertinent mathematical concepts applicable to the case study. By doing so, you can streamline your thinking process and apply appropriate methods with precision.

3. Deconstruction of the Problem: Break down the complex problem into manageable components or steps. This approach enhances clarity and facilitates organized problem-solving.

4. Highlighting Key Data: Emphasize critical information and data supplied within the case study. This practice aids quick referencing during the problem-solving process.

5. Application of Formulas: Leverage pertinent mathematical formulas, theorems, and principles to solve the case study. Accuracy in formula selection and unit usage is paramount.

6. Transparent Workflow Display: Document your solution with transparency, showcasing intermediate calculations and steps taken. This not only helps track progress but also offers insight into your analytical process.

7. Variable Labeling and Definition: For introduced variables or unknowns, offer clear labels and definitions. This eliminates ambiguity and reinforces a structured solution approach.

8. Step Explanation: Accompany each step with an explanatory note. This reinforces your grasp of concepts and demonstrates effective application.

9. Realistic Application: When the case study pertains to real-world scenarios, infuse practical reasoning and logic into your solution. This ensures alignment with real-life implications.

10. Thorough Answer Review: Post-solving, meticulously review your answer for accuracy and coherence. Assess its compatibility with the case study’s context.

11. Solution Recap: Before submission, revisit your solution to guarantee comprehensive coverage of the problem and a well-organized response.

12. Previous Case Study Practice: Boost your confidence by practicing with past case study questions from exams or textbooks. This familiarity enhances your readiness for the question format.

13. Efficient Time Management: Strategically allocate time for each case study question based on its complexity and the overall exam duration.

14. Maintain Composure and Confidence: Approach questions with poise and self-assurance. Your preparation equips you to conquer the challenges presented.

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Case Study- (Surface Areas and Volumes)

Surface Areas and Volumes

CASE STUDY 1:

Adventure camps are the perfect place for the children to practice decision making for themselves without parents and teachers guiding their every move. Some students of a school reached for adventure at Sakleshpur. At the camp, the waiters served some students with a welcome drink in a cylindrical glass and some students in a hemispherical cup whose dimensions are shown below. After that they went for a jungle trek. The jungle trek was enjoyable but tiring. As dusk fell, it was time to take shelter. Each group of four students was given a canvas of area 551m2 . Each group had to make a conical tent to accommodate all the four students. Assuming that all the stitching and wasting incurred while cutting, would amount to 1m2 , the students put the tents. The radius of the tent is 7m.

jagran josh

1. The volume of cylindrical cup is

a) 295.75 cm 3

b) 7415.5 cm 3

c) 384.88 cm 3

d) 404.25 cm 3

Answer:  d) 404.25 cm 3

2. The volume of hemispherical cup is

a) 179.67 cm 3

b) 89.83 cm 3

c) 172.25 cm 3

d) 210.60 cm 3

Answer:  b) 89.83 cm 3

3. Which container had more juice and by how much?

a) Hemispherical cup, 195 cm 3

b) Cylindrical glass, 207 cm 3

c) Hemispherical cup, 280.85 cm 3

d) Cylindrical glass, 314.42 cm 3

Answer:  d) Cylindrical glass, 314.42 cm 3

4. The height of the conical tent prepared to accommodate four students is

Answer:  c) 24m

5. How much space on the ground is occupied by each student in the conical tent

b) 38.5 m 2

Answer:  b) 38.5 m 2

CASE STUDY 2:

jagran josh

The Great Stupa at Sanchi is one of the oldest stone structures in India, and an important monument of Indian Architecture. It was originally commissioned by the emperor Ashoka in the 3rd century BCE. Its nucleus was a simple hemispherical brick structure built over the relics of the Buddha. .It is a perfect example of combination of solid figures. A big hemispherical dome with a cuboidal structure mounted on it. (Take π = 22/7)

1. Calculate the volume of the hemispherical dome if the height of the dome is 21 m –

a) 19404 cu. m

b) 2000 cu .m

c) 15000 cu. m

d) 19000 cu. m

Answer:  a) 19404 cu. m

2. The formula to find the Volume of Sphere is –

a) 2/3 πr 3

b) 4/3 πr 3

Answer:  b) 4/3 πr 3

3. The cloth require to cover the hemispherical dome if the radius of its base is 14m is

a) 1222 sq.m

b) 1232 sq.m

c) 1200 sq.m

d) 1400 sq.m

Answer:  b) 1232 sq.m

4. The total surface area of the combined figure i.e. hemispherical dome with radius 14m and cuboidal shaped top with dimensions 8m 6m 4m is

a)1200 sq. m

b) 1232 sq. m

c) 1392 sq.m

d) 1932 sq. m

Answer:  c) 1392 sq.m

5. The volume of the cuboidal shaped top is with dimensions mentioned in question 4

a) 182.45 m 3

b) 282.45 m 3

Answer:  d) 192 m 3

CASE STUDY 3:

On a Sunday, your Parents took you to a fair. You could see lot of toys displayed, and you wanted them to buy a RUBIK’s cube and strawberry ice-cream for you. Observe the figures and answer the questions:-

jagran josh

1. The length of the diagonal if each edge measures 6cm is

Answers:  d) 6√3

2. Volume of the solid figure if the length of the edge is 7cm is

b) 196 cm 3

c) 343 cm 3

d) 434 cm 3

Answers:  c) 343 cm 3

3. What is the curved surface area of hemisphere (ice cream) if the base radius is 7cm?

a) 309 cm 2

b) 308 cm 2

c) 803 cm 2

d) 903 cm 2

Answers:  b) 308 cm 2

4. Slant height of a cone if the radius is 7cm and the height is 24 cm___

Answers:  b) 25 cm

5. The total surface area of cone with hemispherical ice cream is

a) 858 cm 2

b) 885 cm 2

c) 588 cm 2

d) 855 cm 2

Answers:  a) 858 cm 2

case study questions on surface area and volume class 8

Based on the above information, answer the following questions.

(i) Find the lateral surface area of the Hermika, if the side of cubical part is 8 m.

(ii) The diameter and height of the cylindrical base part are respectively 42 m and 12 m. If the volume of each brick used is 0.01 m 3 , then find the number of bricks used to make the cylindrical base.

(a) 1663200

(b) 1580500

(c) 1765000

(d) 1865000

(iii) If the diameter of the Anda is 42 m, then the volume of the Anda is

(a) 17475 m 3

(b) 18605 m 3

(c) 19404 m 3

(d) 18650 m 3

(iv) The radius of the Pradakshina path is 25 m. If Buddhist priest walks 14 rounds on this path, then find the distance covered by the priest.

(v) The curved surface area of the Anda is

(a) 2856 m 2

(b) 2772 m 2

(c) 2473 m 2

(d) 2652 m 2

case study questions on surface area and volume class 8

(i) After carving out cone from the cylinder,

(ii) Find the slant height of the conical cavity so formed.

(iii) The curved surface area of the conical cavity so formed is

(iv) External curved surface area of the cylinder is

(v) Volume of conical cavity is

case study questions on surface area and volume class 8

(i) The radius of the sphere so formed is

(ii) The volume of the sphere so formed is

(iii) Find the ratio of the volume of sphere to the volume of cylinder.

(iv) Total surface area of the cylinder is

(v) During the conversion of a solid from one shape to another the volume of new shape will

case study questions on surface area and volume class 8

(i) The volume of the cuboidal part is

(ii) Total volume of conical depressions is

(iii) Volume of the wood used in the entire stand is

(iv) Total surface area of cone of radius r is given by

( a ) π r l + π r ²

( b ) 2 π r l + π r²

( c ) π r 2 l + π r ²

( d ) π r l + 2 π r³

(v) If the cost of wood used is Rs 5 per cm 3 , then the total cost of making the pen stand is

case study questions on surface area and volume class 8

(i) Curved surface area of the cylinder made by Meera is

(ii) The ratio of curved surface area of the cylinders made by Meera and Dhara is

(iii) The volume of the cylinder made by Dhara is

(iv) The ratio of the volume of the cylinders made by Meera and Dhara is

(v) When two coins are shifted from Meeras cylinder to Dhara’s cylinder, then

Case Study Questions

(i) (b) : Lateral surface area of Hermika which is cubical in shape = 4a 2 = 4 × (8) 2  = 256 m 2

\frac{22}{7}

= 44 × 21 × 21 = 19404   m 3

\frac{22}{7}

(i) (a) (ii) (d):  Slant height of conical cavity  l = h 2 + r 2

\sqrt{l}

l = 25   c m

(iv) (c)  : External curved surface area of cylinder = 2 π r h

\frac{1}{3}

(iii) (c): ∵  Volume of sphere = Volume of cylinder ∴ Required ratio = 1 : 1

(i) (b): Volume of cuboidal part = l x b x h

= (20 × 15 × 5) cm 3  = 1500 cm 3

\frac{1}{3}

(iii) (d):  Volume of wood used in the entire stand = Volume of cuboidal part – Total volume of conical depressions = 1500 – 2.376 = 1497.624 cm 3

(v) (d):  Cost of wood per cm 3  = Rs 5 ∴  Total cost of making the pen stand = Rs (5 x 1497.624)

= Rs 7488.12

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Unit 13: Surface area and volume

Cube, cuboid, and cylinder.

  • Surface area of a box (cuboid) (Opens a modal)
  • Volume of a rectangular prism (Opens a modal)
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  • RS Aggarwal Solutions Class 8 Chapter-20 Volume and Surface Area of Solids (Ex 20A) Exercise 20.1
  • RS Aggarwal Solutions

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RS Aggarwal Solutions Class 8 Chapter-20 Volume and Surface Area of Solids (Ex 20A) Exercise 20.1 - Free PDF

The RS Aggarwal Class 8 Chapter 20 is important in the syllabus of Class 8. The PDF here is formulated to cover all the aspects of this Chapter and give a clear insight on how to learn the concepts and implement them in the questions. The experts at Vedantu have meticulously worked on this topic of RS Aggarwal Class 8 Chapter 20 Exercise 20A and came up with a short yet well-explained concept so that all the students can understand the concept easily and do not have any doubts further. Practice more questions from RS Aggarwal Class 8 Ex 20A for better scoring. Vedantu is a platform that provides free NCERT Solution and other study materials for students. You can also download NCERT Solution for Class 8 Science and NCERT Solutions for Class 8 Maths to help you to revise the complete syllabus and score more marks in your examinations.

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Class 8 RS Aggarwal Exercise 20A Free PDF Download

The RS Aggarwal Class 8 Ex 20A has all the information needed to solve the questions and will help you very much at the time of your examination. If the PDF of the RS Aggarwal Class 8 20A solution is downloaded, It will be available to you all the time and can come in handy whenever you want to revise the topic. For all the students who want to excel in the examination, the solutions can be of great help. The important points and the formulae are listed very precisely and clearly. Our PDF solutions help students to assess their understanding of the topic better.

RS Aggarwal Class 8 Exercise 20A Solution

Chapter - surface area and volume.

The Surface Area and Volume Class 8 will cover the concepts of how to find the Volume and Surface Areas of certain solids. All the formulae related to the cube, cuboid, cylinder, cone, etc., are mentioned and the perfect examples illustrating these formulae are provided in a detailed manner. The main focus is on the Volume, lateral Surface Area, and total Surface Area. The application of using these formulae and finding the required elements is explained beautifully by our subject experts in the Surface Area and Volume Class 8.

Why is RS Aggarwal Class 8 Chapter 20 Important?

The PDF covers all the important formulae of the questions asked in the exam.

Important points and topics are explained easily.

The concepts are very well explained by the subject matter experts which will make understanding effortless.

The PDF can be downloaded easily and this will make the article very handy for last-minute revision.

The important questions are prioritized and listed in this article.

Our solutions come with Chapter-wise strategies for students to prepare for exams.

Practising RS Aggarwal Class 8 Exercise 20A Solution will help you build conceptual knowledge about the subject.

About the Chapter

This Chapter is primarily concerned with the Volumes and Surface Areas of a cuboid and a cube. Some applications of these formulae to simple problems from everyday life will be discussed as well. Students who are having difficulty solving problems can use RS Aggarwal Class 8. Our expert faculty team creates solutions with the utmost care to ensure that students understand the concepts clearly. Students can use the RD Sharma textbook as a reference source when studying for their board exams. This Chapter's solutions are available in PDF format and can be downloaded from the links provided below.

Volumes and Surface Areas of a Cuboid and a Cube Chapter 20 contains four exercises, and the RS Aggarwal Class 8 Solutions on this page provide answers to the questions in each exercise. Let's take a look at the concepts covered in this Chapter.

Regions of space.

The Volume of a body-formed space region.

A Volume unit that is universally accepted.

The formula for calculating a cuboid's Volume.

A cube's Volume is its Volume.

Other Volume units are commonly used.

A cuboid's and a cube's Surface Areas

The Surface Area of a room's walls.

Problems of various kinds.

Any three-dimensional geometrical shape's Surface Area and Volume are calculated. The Surface Area of a given object is the Area or region occupied by the object's Surface. Volume, on the other hand, is the amount of space available in an object.

There are various shapes and sizes in geometry, such as the sphere, cube, cuboid, cone, cylinder, and so on. Each shape has both a Surface Area and a Volume. However, in the case of two-dimensional figures such as squares, circles, rectangles, triangles, and so on, we can only measure the Area covered by these figures and no Volume is available. Let us now look at the Surface Area and Volume formulas for various 3D shapes.

What Exactly is Surface Area?

The Area is the space occupied by a two-dimensional flat Surface. It is expressed in square units. Surface Area refers to the Area occupied by a three-dimensional object's outer Surface. It's also expressed in square units.

In General, There are Two Kinds of Areas:

Surface area total.

Curved Surface Area/Lateral Surface Area

The total Surface Area includes the base(s) and the curved portion. It is the total Area covered by the object's Surface. If the shape has a curved Surface and a flat base, the total Area is the sum of the two Areas.

The Surface Area that is Curved

The Area of only the curved part of the shape, excluding its base, is referred to as the curved Surface Area (s). For shapes such as a cylinder, it is also known as lateral Surface Area.

What Exactly is Volume?

Volume is the amount of space that an object or substance takes up, measured in cubic units. Two-dimensional objects lack Volume and instead focus on the Area. The Volume of a circle, for example, cannot be found, but the Volume of a sphere can. Because a sphere is a three-dimensional shape, this is true.

RS Aggarwal Solutions Class 8 Ex 20A Chapterwise Weightage

RS Aggarwal Class 8 Exercise 20A solution is an important Chapter from the exam point of view. The formula of Volume of solids, LSA, and TSA of solids will be asked in the very short answer type format. There will be questions to solve for radius, the height of solids by giving some information about the solid in the short-answer type questions. The long answer type questions will have questions that will be application-based and involve real-time examples related to the formulae mentioned in the Chapter. We can expect 5-6 questions from RS Aggarwal Class 8 Chapter 20. The best way to improve your Maths score is to practice all these Class 8 RS Aggarwal Exercise 20A Questions daily.

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FAQs on RS Aggarwal Solutions Class 8 Chapter-20 Volume and Surface Area of Solids (Ex 20A) Exercise 20.1

1. The length of a geometry box is 20 cm, its breadth is 5 cm, and has height of 1 cm. Find the volume of the geometry box.

The length of geometry box = 20 cm

The length of geometry box = 5 cm

The length of geometry box = 1 cm

The geometry box is in the shape of a cuboid.

So, the Volume of the geometry box is the same as the Volume of the cuboid.

The Volume of cuboid = lbh

Volume of geometry box = 20 cm * 5 cm * 1 cm = 100 cubic cm.

 Hence, the Volume of the cuboid is 100 cubic cm.

2. A cheese cube has a length of 5 cm and is further cut into smaller cubes which have a volume of 1 cubic cm each. Find the number of such smaller cubes obtained.

Length of larger cube = 5cm

The Volume of cube = side 3

The Volume of the larger cube = 5 3 = 125 cubic cm.

Number of cubes obtained = (Volume of the larger cube)/(Volume of smaller cubes)

Number of cubes = 125/1 = 125

Hence, the number of cubes obtained after cutting them into smaller cubes is 125.

3. Where can I find useful Math study materials for Class 9?

Everything you need can be found on the Vedantu app or website. These resources are created by experts in the field, and the information is accurate and dependable. Students will be able to find revision notes, important questions, question papers, and much more! There are no fees or costs associated with these study materials. All students need to do is sign in, and then they can download whatever they want in pdf format. You can benefit from these free resources, which will undoubtedly help you ace your exams.

4. How can I do well in Class 8 Math?

The only way to do well in Class 9 Maths is to practise. Complete all of the Chapter exercises. This will enhance your problem-solving abilities as well as your speed and efficiency. Important formulas, definitions, and equations can be written down in a notebook and reviewed on a regular basis. Solve previous year's sample papers and question papers within a time limit. This will familiarise you with the paper pattern and question type, as well as help you improve your time management skills. Revise on a regular basis to ensure that you retain everything you've learned for a longer period of time.

5. A rectangular water reservoir contains 105 m 3 of water. Find the depth of the water in the reservoir if its base measures 12 m by 3.5 m.

Given details are,

The capacity of water reservoir = 105 m 3

Length of base of reservoir = 12 m

Width of base = 3.5 m

Let the depth of reservoir be ‘hm

l × b × h = 105

h = 105 / (l × b)

= 105 / (12×3.5)

∴ The depth of the reservoir is 2.5 m

case study questions on surface area and volume class 8

  • Mensuration
  • Volume and Surface Area

Class 8 NCERT (CBSE and ICSE) Volume and Surface Area

Student assignments, create unlimited student assignments., online practice, online tests, printable worksheets and tests.

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Class 8 , Exercise 37 , Volume & Surface Area of Solid Surfaces

Class 8: Volume and Surface Area of Solids – Exercise 37

case study questions on surface area and volume class 8

Question 1. Find the volume, the total surface area and the lateral surface area of the cuboid having:

Length (l)= 24 \ cm, \ breadth(b)= 16 \ cm\ and \ height(h) = 7.5 \ cm

i) Area of walls excluding the doors are windows

= (l\times h+b\times h)\times 2-(Area \ of \ Doors)\times 1-(Area \ of \ Window)\times 2

Area of walls excluding the doors are windows

= (l\times h+b\times h)\times 2-(Area \ of \ Doors)\times 5-(Area \ of \ Window)\times 4

Multiplying the above three expressions we get

l^2\times b^2\times h^2=120\times 72\times 60 \Rightarrow Volume= \sqrt{(120\times 72\times 60)}=720\ cm^3 

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Free Printable Surface Area Worksheets for 8th Class

Math teachers, discover a collection of free printable Surface Area worksheets tailored for Class 8 students. Enhance your lessons and help students explore the fascinating world of geometry with these comprehensive resources provided by Quizizz.

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Explore printable Surface Area worksheets for 8th Class

Surface Area worksheets for Class 8 are an essential tool for teachers to help their students master the concepts of geometry and area in math. These worksheets provide a variety of problems that cover different shapes and objects, allowing students to practice calculating surface area using the appropriate formulas. With a focus on Class 8 math curriculum, these worksheets are designed to challenge students and enhance their understanding of geometry, while also reinforcing their skills in solving problems related to area. Teachers can use these worksheets as in-class activities, homework assignments, or even as assessment tools to gauge their students' progress in mastering surface area concepts. Surface Area worksheets for Class 8 are a valuable resource for teachers looking to improve their students' math skills and understanding of geometry and area.

Quizizz is an excellent platform for teachers that not only offers Surface Area worksheets for Class 8 but also provides a wide range of other math and geometry resources. This interactive platform allows teachers to create engaging quizzes and games that can be used in the classroom or assigned as homework. With Quizizz, teachers can easily track their students' progress and identify areas where they may need additional support or practice. In addition to Surface Area worksheets for Class 8, Quizizz offers resources covering various topics in math, such as algebra, fractions, and measurement. Teachers can also find resources for other subjects, making Quizizz a one-stop-shop for all their educational needs. By incorporating Quizizz into their lesson plans, teachers can enhance their students' learning experience and help them excel in math, geometry, and area concepts.

case study questions on surface area and volume class 8

RS Aggarwal Solutions Class 8 Exercise 20A Chapter 20 Volume and Surface Area of Solids

Get Latest Edition of RS Aggarwal Solutions Class 8 Chapter 20 Volume and Surface Area of Solids Exercise 20A. Volume and Surface Area of Solids RS Aggarwal Class 8 Maths Solutions help you to revise the complete syllabus and score excellent marks.

RS Aggarwal Solutions Class 8 Chapter 20 Ex 20A

RS Aggarwal Solutions Class 8 Chapter 20 Volume and Surface Area of Solids Exercise 20A 00001

Also, check the solutions of other exercises from below.

  • Chapter 20 Volume and Surface Area of Solids Exercise 20A
  • Chapter 20 Volume and Surface Area of Solids Exercise 20B
  • Chapter 20 Volume and Surface Area of Solids Exercise 20C
  • Chapter 20 Volume and Surface Area of Solids CCE Test Paper

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  • CBSE Class 10 Study Material

CBSE Class 10 Maths Case Study Questions for Chapter 13 - Surface Areas and Volumes (Published By CBSE)

Check case study questions for cbse class 10 maths chapter 13 - surface areas and volumes. this question bank based on case study has been published by the board for class 10 mathematics..

Gurmeet Kaur

Case study questions for CBSE Class 10 Maths Chapter 13 - Surface Areas and Volumes are published by the CBSE board. Students can solve these questions to acquaint themselves with the new type of questions. Answers to all the questions have been provided with them. These case study questions are quite helpful to prepare for the CBSE Class 10 Maths Exam 2021-2022.

Case Study Questions for Class 10 Maths Chapter 10 - Surface Areas and Volumes

CASE STUDY 1:

Adventure camps are the perfect place for the children to practice decision making for themselves without parents and teachers guiding their every move. Some students of a school reached for adventure at Sakleshpur. At the camp, the waiters served some students with a welcome drink in a cylindrical glass and some students in a hemispherical cup whose dimensions are shown below. After that they went for a jungle trek. The jungle trek was enjoyable but tiring. As dusk fell, it was time to take shelter. Each group of four students was given a canvas of area 551m2 . Each group had to make a conical tent to accommodate all the four students. Assuming that all the stitching and wasting incurred while cutting, would amount to 1m2 , the students put the tents. The radius of the tent is 7m.

case study questions on surface area and volume class 8

1. The volume of cylindrical cup is

a) 295.75 cm 3

b) 7415.5 cm 3

c) 384.88 cm 3

d) 404.25 cm 3

Answer: d) 404.25 cm 3

2. The volume of hemispherical cup is

a) 179.67 cm 3

b) 89.83 cm 3

c) 172.25 cm 3

d) 210.60 cm 3

Answer: b) 89.83 cm 3

3. Which container had more juice and by how much?

a) Hemispherical cup, 195 cm 3

b) Cylindrical glass, 207 cm 3

c) Hemispherical cup, 280.85 cm 3

d) Cylindrical glass, 314.42 cm 3

Answer: d) Cylindrical glass, 314.42 cm 3

4. The height of the conical tent prepared to accommodate four students is

Answer: c) 24m

5. How much space on the ground is occupied by each student in the conical tent

b) 38.5 m 2

Answer: b) 38.5 m 2

CASE STUDY 2:

case study questions on surface area and volume class 8

The Great Stupa at Sanchi is one of the oldest stone structures in India, and an important monument of Indian Architecture. It was originally commissioned by the emperor Ashoka in the 3rd century BCE. Its nucleus was a simple hemispherical brick structure built over the relics of the Buddha. .It is a perfect example of combination of solid figures. A big hemispherical dome with a cuboidal structure mounted on it. (Take π = 22/7)

1. Calculate the volume of the hemispherical dome if the height of the dome is 21 m –

a) 19404 cu. m

b) 2000 cu .m

c) 15000 cu. m

d) 19000 cu. m

Answer: a) 19404 cu. m

2. The formula to find the Volume of Sphere is -

a) 2/3 πr 3

b) 4/3 πr 3

c) 4 πr 2

d) 2 πr 2

Answer: b) 4/3 πr 3

3. The cloth require to cover the hemispherical dome if the radius of its base is 14m is

a) 1222 sq.m

b) 1232 sq.m

c) 1200 sq.m

d) 1400 sq.m

Answer: b) 1232 sq.m

4. The total surface area of the combined figure i.e. hemispherical dome with radius 14m and cuboidal shaped top with dimensions 8m 6m 4m is

a)1200 sq. m

b) 1232 sq. m

c) 1392 sq.m

d) 1932 sq. m

Answer: c) 1392 sq.m

5. The volume of the cuboidal shaped top is with dimensions mentioned in question 4

a) 182.45 m 3

b) 282.45 m 3

Answer: d) 192 m 3

CASE STUDY 3:

On a Sunday, your Parents took you to a fair. You could see lot of toys displayed, and you wanted them to buy a RUBIK’s cube and strawberry ice-cream for you. Observe the figures and answer the questions:-

case study questions on surface area and volume class 8

1. The length of the diagonal if each edge measures 6cm is

a) 3√3

b) 3√6

c) √12

d) 6√3

Answers: d) 6√3

2. Volume of the solid figure if the length of the edge is 7cm is

b) 196 cm 3

c) 343 cm 3

d) 434 cm 3

Answers: c) 343 cm 3

3. What is the curved surface area of hemisphere (ice cream) if the base radius is 7cm?

a) 309 cm 2

b) 308 cm 2

c) 803 cm 2

d) 903 cm 2

Answers: b) 308 cm 2

4. Slant height of a cone if the radius is 7cm and the height is 24 cm___

Answers: b) 25 cm

5. The total surface area of cone with hemispherical ice cream is

a) 858 cm 2

b) 885 cm 2

c) 588 cm 2

d) 855 cm 2

Answers: a) 858 cm 2

Also Check:

CBSE Class 10 Maths Case Study Questions - All Chapters

Tips to Solve Case Study Based Questions Accurately

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  • Math Article

Mensuration Class 8

Mensuration Class 8 Chapter 11 notes,  important questions and formulas are mentioned here. Class 8 Chapter 11 Mensuration materials are provided here as per CBSE syllabus (2022-2023) and latest exam pattern. Get through the formulas and practise the concept of mensuration with the help of given examples. Mensuration chapter has been further introduced in Class 10, hence it is necessary that each student learns its basic concept first. Mensuration basically means the measurement of the area and perimeter of different geometrical shapes such as triangles, trapeziums, rectangles, etc. Preparing this chapter from this article will help students in scoring good marks in the final exams.

Mensuration Class 8 Notes

Mensuration deals with the measurement of area, perimeter, surface area and volume of different types of shapes.

Let us recall the area of all two-dimensional shapes.

Mensuration Class 8 – Area of Trapezium

By constructing EC || AB, we can split the given figure (AEDCBA) into two parts (Triangle ECD right-angled at C and Rectangle AECB), Here, b = a + c = 30 m

Mensuration class 8 example

Now, Area of Triangle DCE:

1/2 × CD × EC= 1/2 × c × s

h = 1/2 ×10× 12 = 60 m 2

Also, Area of rectangle AECB = AB × BC = h × a=12 × 20=240 m 2

Therefore, Area of trapezium AEDB = Area of Triangle DCE + Area of rectangle AECB = 60 + 240 = 300 =300m 2

Area of Trapezium = Height/2 (Sum of parallel sides) = 1/2 h(a+b)

Mensuration Class 8 – Area of General Quadrilateral

Mensuration class 8 - area of quadrilateral

Diagonal AC divides the given quadrilateral into two triangles i.e. Triangle ABC and Triangle ADC.

Now, Area of Quadrilateral ABCD = Area of Triangle ABC + Area of Triangle ADC.

=1/2 × AC × h 1 + 1/2 × AC × h 2 =1/2 × d × (h 1 +h 2 )

Where, d = The length of diagonal of a quadrilateral.

The area of other polygons (pentagon, hexagon, etc.) can be determined, by splitting them into a number of triangles and finding the respective areas.

Mensuration Class 8 Formulas

The important formulas covered in this chapter are as follows:

  • d1 and d2 are the diagonals of the rhombus
  • d is the diagonal of a special quadrilateral which is divided into two triangles
  • h 1  and h 2  are the two perpendiculars from the vertices of a quadrilateral to its diagonal
  • l, b and h denotes length, breadth and height of the cuboid
  • r represents the radius of the cylindrical base
  • a is the side of the cube

Class 8 Mensuration Important Points

  • The trapezium and rhombus are the figures represented in the two-dimensional plane. Whereas Cuboid, Cube and Cylinder are three-dimensional solid shape.
  • The surface area of a solid shape is the sum of the areas of its faces.
  • Amount of region occupied by a solid shape is called its volume.

Volume and Capacity

Volume and capacity are almost similar to each other.

  • A volume is the amount of space occupied by a three-dimensional object
  • Capacity is the quantity of liquid contained in an object
  • 1 mL = 1 cm 3
  • 1 L = 1000 cm 3
  • 1 m 3 = 1000000 cm 3 = 1000 L

More Articles for Class 8

Solved questions for mensuration class 8.

Example 1: Find the area of a square whose side is 30 m.

Solution: The area of square = (Side) 2

Given, side = 30 m.

Then, area of square = (30) 2 = 900 m 2 .

Example 2: Find the perimeter of a triangle with two equal sides of 5 cm and one side of 10 cm.

Solution: We know that,

perimeter of triangle = sum of all the three sides

= (5 + 5 + 10)

Example 3: Calculate the area of a trapezium whose height is 4 cm and length of parallel sides are 5 cm and 3 cm, respectively. Solution: Given, Height of the trapezium = 4cm and length of parallel sides are 5cm and 3cm respectively.

Area of trapezium =  height x (sum of parallel sides)/2

A = 4 x (5 + 3)/2

A = 4 x 8/2

A = 16 sq.cm.

Example 4: Find the area of special quadrilateral whose diagonal length is 6 cm. And the lengths of two perpendiculars on given diagonal from the vertices are 3 cm and 4 cm.

Solution: Given, diagonal of quadrilateral, d = 6 cm.

Let the length of two perpendiculars be h 1 = 3 cm and h 2 = 4 cm.

As per the formula of quadrilateral, we can write,

Area of quadrilateral ABCD =   ½ x d x (h 1  + h 2 )

A = 1/2 x 6 x (3 + 4)

= 1/2 x 6 x 7

Example 5: Find the area of rhombus in which the length of its two diagonals is 8.5cm and 10 cm.

Solution: We know;

Area of rhombus =  ½ x d 1 x d 2

A = 1/2 x 8.5 x 10

A = 42.5 sq.cm.

Frequently Asked Questions on Mensuration Class 8

How many cubic centimetres make 1 litre.

1 litre = 1000 cm 3 and 1 millilitre = 1 cm 3 .

What is the curved surface area of a cylinder?

The curved surface area of a cylinder is given by 2𝜋rh square units, where r is the radius of circular ends and h is the height of the cylinder.

What is the area of a special quadrilateral?

The area of a special quadrilateral is given by ½ x d x (h 1 + h 2 ) square units, where d is the diagonal which divided the quadrilateral into two triangles and h 1 , h 2 are the two perpendiculars from the vertices of a quadrilateral to its diagonal.

What is the area of a parallelogram?

The area of a parallelogram is given by b × h, where h is the altitude of the parallelogram on the base b.

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case study questions on surface area and volume class 8

CBSE 10th Standard Maths Subject Surface Areas and Volumes Case Study Questions 2021

By QB365 on 22 May, 2021

QB365 Provides the updated CASE Study Questions for Class 10 Maths, and also provide the detail solution for each and every case study questions . Case study questions are latest updated question pattern from NCERT, QB365 will helps to get  more marks in Exams

QB365 - Question Bank Software

10th Standard CBSE

Final Semester - June 2015

Case Study Questions

case study questions on surface area and volume class 8

(ii) The diameter and height of the cylindrical base part are respectively 42 m and 12 m. If the volume of each brick used is 0.01 m 3 , then find the number of bricks used to make the cylindrical base.

(iii) If the diameter of the Anda is 42 m, then the volume of the Anda is

(iv) The radius of the Pradakshina path is 25 m. If Buddhist priest walks 14 rounds on this path, then find the distance covered by the priest.

(v) The curved surface area of the Anda is

case study questions on surface area and volume class 8

(ii) Find the slant height of the conical cavity so formed.

(iii) The curved surface area of the conical cavity so formed is

(iv) External curved surface area of the cylinder is

(v) Volume of conical cavity is

case study questions on surface area and volume class 8

(ii) The volume of the sphere so formed is

(iii) Find the ratio of the volume of sphere to the volume of cylinder.

(iv) Total surface area of the cylinder is 

(v) During the conversion of a solid from one shape to another the volume of new shape will 

case study questions on surface area and volume class 8

(ii) Total volume of conical depressions is 

(iii) Volume of the wood used in the entire stand is

(iv) Total surface area of cone of radius r is given by

(v) If the cost of wood used is Rs 5 per cm 3 , then the total cost of making the pen stand is

case study questions on surface area and volume class 8

(ii) The ratio of curved surface area of the cylinders made by Meera and Dhara is

(iii) The volume of the cylinder made by Dhara is

(iv) The ratio of the volume of the cylinders made by Meera and Dhara is

(v) When two coins are shifted from Meeras cylinder to Dhara's cylinder, then

*****************************************

Cbse 10th standard maths subject surface areas and volumes case study questions 2021 answer keys.

(i) (b) : Lateral surface area of Hermika which is cubical in shape = 4a 2 = 4 x (8) 2 = 256 m 2 (ii) (a) : Diameter of cylindrical base = 42 m \(\therefore\) Radius of cylindrical base (r) = 21 m Height of cylindrical base (h) = 12 m \(\therefore\) Number of bricks used  \(=\frac{\frac{22}{7} \times 21 \times 21 \times 12}{0.01}\) = 1663200 (iii) (c) : Given, diameter of Anda which is hemispherical in shape = 42 m \(\Rightarrow\) Radius of Anda (r) = 21 m \(\therefore \quad \text { Volume of } A n d a =\frac{2}{3} \pi r^{3}=\frac{2}{3} \times \frac{22}{7} \times 21 \times 21 \times 21 \) \(=44 \times 21 \times 21=19404 \mathrm{~m}^{3}\) (iv) (d): Given, radius of Pradakshina Path (r) = 25 m \(\therefore\) Perimeter of path =  \(2\pi r\) \(=\left(2 \times \frac{22}{7} \times 25\right) \mathrm{m}\) · . Distance covered by priest  \(=14 \times 2 \times \frac{22}{7} \times 25\) = 2200 m (v) (b): \(\because\) Radius of Anda (r) = 21 m \(\therefore\) Curved surface area of Anda =  \(2\pi r^{2}\) \(=2 \times \frac{22}{7} \times 21 \times 21=2772 \mathrm{~m}^{2}\)

(i) (a) (ii) (d): Slant height of conical cavity  \(l=\sqrt{h^{2}+r^{2}}\) \(=\sqrt{(24)^{2}+(7)^{2}}=\sqrt{576+49}=\sqrt{625}=25 \mathrm{~cm}\) (iii) (b): Curved surface area of conical cavity =  \(\pi r l\) \(=\frac{22}{7} \times 7 \times 25=550 \mathrm{~cm}^{2}\) (iv) (c) : External curved surface area of cylinder  \(=2 \pi r h=2 \times \frac{22}{7} \times 7 \times 24=1056 \mathrm{~cm}^{2}\) (v) (a): Volume of conical cavity  \(=\frac{1}{3} \pi r^{2} h\) \(=\frac{1}{3} \times \frac{22}{7} \times 7 \times 7 \times 24=1232 \mathrm{~cm}^{3}\)

(i) (b): Since, volume of sphere = volume of cylinder \(\Rightarrow \frac{4}{3} \pi R^{3}=\pi r^{2} h\) where R, r are the radii of sphere and cylinder respectively. \(\Rightarrow R^{3}=\frac{6 \times 6 \times 8 \times 3}{4}=(6)^{3} \Rightarrow R=6 \mathrm{~cm}\) \(\therefore\)   Radius of sphere = 6 cm (ii) (a): Volume of sphere  \(=\frac{4}{3} \pi R^{3}\) \(=\frac{4}{3} \times \frac{22}{7} \times 6 \times 6 \times 6=905.14 \mathrm{~cm}^{3}\) (iii) (c): \(\because\) Volume of sphere = Volume of cylinder \(\therefore\) Required ratio = 1 : 1 (iv) (a): Total surface area of the cylinder  \(=2 \pi r(r+h)\) \(=2 \times \frac{22}{7} \times 6(6+8)=2 \times \frac{22}{7} \times 6 \times 14=528 \mathrm{~cm}^{2}\) (v) (c)

(i) (b): Volume of cuboidal part = 1 x b x h = (20 x 15 x 5) cm 3  = 1500 cm 3 (ii) (c): Radius of conical depression, r = 0.6 cm Height of conical depression, h = 2.1 cm \(\therefore\) Total volume of conical depressions  \(=3 \times \frac{1}{3} \pi r^{2} h\) \(=\frac{22}{7} \times 0.6 \times 0.6 \times 2.1=\frac{2.376}{1000}-2.376 \mathrm{~cm}^{3}\) (iii) (d): Volume of wood used in the entire stand = Volume of cuboidal part - Total volume of conical depressions = 1500 - 2.376 = 1497.624 cm 3 (iv) (a) (v) (d): Cost of wood per cm 3 = Rs 5 \(\therefore\) Total cost of making the pen stand = Rs (5 x 1497.624) = Rs 7488.12

We have, radius of each coin = 3.5 cm \(=\frac{35}{10} \mathrm{~cm}=\frac{7}{2} \mathrm{~cm}\) Thickness of each coin  \(=0.5 \mathrm{~cm}=\frac{1}{2} \mathrm{~cm}\) So,height of cylinder made by Meera (h1)  \(=12 \times \frac{1}{2}=6 \mathrm{~cm}\) and height of cylinder made by Dhara (h2) \(=8 \times \frac{1}{2}=4 \mathrm{~cm}\) (i) (b): Curved surface area of cylinder made by Meera  \(=2 \times \frac{22}{7} \times \frac{7}{2} \times 6=132 \mathrm{~cm}^{2}\) (ii) (b): Required ratio \(=\frac{\text { Curved surface area of cylinder made by Meera }}{\text { Curved surface area of cylinder made by Dhara }}\) \(=\frac{2 \pi r h_{1}}{2 \pi r h_{2}}=\frac{h_{1}}{h_{2}}=\frac{6}{4}=\frac{3}{2} \text { i.e., } 3: 2\) (iii) (a): Volume of cylinder made by Dhara  \(=\pi r^{2} h_{2}\) \(=\frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} \times 4=154 \mathrm{~cm}^{3}\) (iv) (c): Required ratio \(=\frac{\text { Volume of cylinder made by Meera }}{\text { Volume of cylinder made by Dhara }} \) \(=\frac{\pi r^{2} h_{1}}{\pi r^{2} h_{2}}=\frac{h_{1}}{h_{2}}=\frac{6}{4}=\frac{3}{2} \text { i.e., } 3: 2\) (v) (a): When two coins are shifted from Meera's cylinder to Dhara's cylinder, then length of both cylinders become equal. So, volume of both cylinders become equal

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case study questions on surface area and volume class 8

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IMAGES

  1. Surface Area And Volume Worksheet Class 8

    case study questions on surface area and volume class 8

  2. Surface Area And Volume Prisms Worksheet Pdf

    case study questions on surface area and volume class 8

  3. NCERT Solutions Class 9 Maths Chapter 13 Surface Areas and Volumes

    case study questions on surface area and volume class 8

  4. the volume and surface area posters are available for students to learn

    case study questions on surface area and volume class 8

  5. Selina Solutions Concise Maths Class 8 Chapter 21 Surface Area, Volume

    case study questions on surface area and volume class 8

  6. grade 9 surface area and volume math practice questions tests

    case study questions on surface area and volume class 8

VIDEO

  1. PRACTICE SET 9.1

  2. ICSE: Class 8 || Surface area, volume and capacity || Chapter 21 || Selina || Concise Mathematics ||

  3. Ratna Sagar Class 8 Mathematics || Chapter 19 Surface Area and Volume of Solids|| Ex 19A Sol(Part 1)

  4. Case study 93

  5. Volume and surface Area of Solids| Class 8 Exercise 20A Question 24| RS Aggarwal|Learn maths

  6. Surface Area And Volume का जबरदस्त Explanation

COMMENTS

  1. Case Study Class 8 Surface Area and Volumes

    Case Study Class 8 Surface Area and Volumes | I Did It Mathematics Class 8 | Anupama Rathi-----...

  2. RD Sharma Solutions for Class 8 Chapter 22 Mensuration

    ∴ Ratio of their curved surface area is 10:9. 8. The ratio between the curved surface area and the total surface area of a right circular cylinder is 1:2. Prove that its height and radius are equal. Solution: We have, Let radius of cylinder be 'r' Let height of cylinder be 'h' Curved surface area of cylinder / total surface area of ...

  3. PDF Class-viii Sub-mathematics Mensuration(Surface Area and Volume ...

    a) volume b)lateral surface area. c) total surface area d)none of these. 5. The volume of a cuboid whose length, breadth and height are 2a, 3a and 4a is. a) b)24a3 c)12a3 d)none of these. 6. The curved surface area of a right circular cylinder of radius 2r and height 2h is. a) b)4Πrh c)8Πrh d)none of these. 7.

  4. Case Study Questions for Class 8 Maths

    12. Previous Case Study Practice: Boost your confidence by practicing with past case study questions from exams or textbooks. This familiarity enhances your readiness for the question format. 13. Efficient Time Management: Strategically allocate time for each case study question based on its complexity and the overall exam duration. 14.

  5. Case Study- (Surface Areas and Volumes)

    SURFACE AREA AND VOLUME (EX-13.2)Class-9th; SURFACE AREA AND VOLUME EXERCISE 13.3; ... Surface Areas and Volumes . CASE STUDY 1: ... answer the following questions. (i) Curved surface area of the cylinder made by Meera is (a) 144 cm 2 (b) 132 cm 2 (c) 154 cm 2 (d) 142 cm 2

  6. Important Questions for CBSE Class 8 Maths Chapter 11

    Free PDF download of Important Questions with solutions for CBSE Class 8 Maths Chapter 11 - Mensuration prepared by expert Mathematics teachers from latest edition of CBSE(NCERT) books. ... Math is a tricky subject to study, and thus having proper notes can boost up the studying procedure and eventually your grades. ... Volume (b) Surface area ...

  7. Surface area and volume

    Class 8. 14 units · 61 skills. Unit 1. Rational and irrational numbers. Unit 2. Parallel lines and transversal. ... Cylinder volume & surface area (Opens a modal) Practice. Volume of rectangular prisms. 7 questions. Practice. Volume of cylinders. 4 questions. Practice. Our mission is to provide a free, world-class education to anyone, anywhere.

  8. RD Sharma Solutions for Class 8 Chapter 21 Mensuration

    Chapter 21- Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) contains four exercises, and the RD Sharma Class 8 Solutions present in this page provide solutions to the questions given in each exercise. Now, let us have a look at the concepts discussed in this chapter.

  9. RS Aggarwal Class 8 Mathematics Solutions for Chapter-20 Volume and

    If, on the other hand, we want to store milk or water in a container or food grains in a godown, we'll need to calculate the volume. All the Exercise questions with solutions in Chapter-20 Volume and Surface Area of Solids are given below: Exercise (Ex 20A) 20.1. Exercise (Ex 20B) 20.2. Exercise (Ex 20C) 20.3.

  10. RS Aggarwal Solutions Class 8 Chapter-20 Volume and Surface Area of

    Free PDF download of RS Aggarwal Solutions Class 8 Chapter-20 Volume and Surface Area of Solids (Ex 20A) Exercise 20.1 solved by Expert Mathematics Teachers on Vedantu.com. All Exercise 20.1 Questions with Solutions for Class 8 RS Aggarwal to help you to revise complete Syllabus and Score More marks.

  11. CBSE Class 8 Maths Surface Area and Volume of Cylinder

    Surface Area and Volume of Cylinder ,Mensuration - Get topics notes, Online test, Video lectures, Doubts and Solutions for CBSE Class 8 on TopperLearning.

  12. Class 8 (Maths) Surface Area and Volume Flashcards

    Curved surface area of cylinder. = 2πr x h. Volume of cuboid. = l x b x h. Volume of cube. =s³. Volume of cylinder. = πr²h. Study with Quizlet and memorize flashcards containing terms like Surface area of cuboid, Surface area of cube, Surface area of cylinder and more.

  13. Class 8 NCERT (CBSE and ICSE) Volume and Surface Area

    Volume and Surface Area problems, practice, tests, worksheets, questions, quizzes, teacher assignments | Class 8 | NCERT (CBSE and ICSE)

  14. Selina Solutions Concise Maths Class 8 Chapter 21 Surface Area, Volume

    Question 5. Find the volume and total surface area of a cube whose edge is: (i) 8 cm. Solution:-Edge of the given cube =8cm. We know that (ii) 2m 40 cm. Solution:-(ii)Edge of the given cube =2 m 40 cm=2.40 m. We know that. Question 6. Find the length of each edge of a cube, if its volume is: Question 7. The total surface area of a cube is 216 ...

  15. Class 8: Volume and Surface Area of Solids

    Volume of a cuboid . Question 8. The volume of the cuboid is . Its length is and its breadth and height Are in the ratio of . Find the breadth and height of the cube. Answer: Volume of a cuboid . Question 9. The surface area of the cuboid is . Its length and breadth are respectively. Find its height. Answer: Surface Area of a cuboid . Question 10.

  16. Case study questions for class 8 …

    CBSE, JEE, NEET, CUET. Question Bank, Mock Tests, Exam Papers. NCERT Solutions, Sample Papers, Notes, Videos. Install Now. Case study questions for class 8 topic surface area and volume and understanding quadrilaterals. Report. Posted by Ankita Sharma 2 years, 3 months ago. CBSE > Class 09 > Mathematics. 0 answers.

  17. Free Printable Surface Area Worksheets for 8th Class

    Surface Area And Volume III 10 Q. 8th - 10th Surface Areas 9 Q. 8th - 10th Surface Area of Prisms 11 Q. 7th - 8th Surface Area of Prisms 12 Q. 4th - 8th ... In addition to Surface Area worksheets for Class 8, Quizizz offers resources covering various topics in math, such as algebra, fractions, and measurement. ...

  18. RS Aggarwal Solutions Class 8 Exercise 20A Chapter 20 Volume and

    RS Aggarwal Solutions Class 8 Chapter 20 Ex 20A. Also, check the solutions of other exercises from below. Chapter 20 Volume and Surface Area of Solids Exercise 20A. Chapter 20 Volume and Surface Area of Solids Exercise 20B. Chapter 20 Volume and Surface Area of Solids Exercise 20C. Chapter 20 Volume and Surface Area of Solids CCE Test Paper.

  19. 9th Maths Surface Case Study Questions and Answers 2022-23

    Class 9th Maths - Surface Case Study Questions and Answers 2022 - 2023. QB365 provides a detailed and simple solution for every Possible Case Study Questions in Class 9th Maths Subject - Surface, CBSE. It will help Students to get more practice questions, Students can Practice these question papers in addition to score best marks.

  20. Class 9 Maths Case Study Questions of Chapter 13 Surface Areas and

    Case Study/Passage-Based Questions. Case Study 1: A class teacher brings some clay in the classroom to teach the topic of mensuration. First she forms a cylinder of radius 6 cm and height 8 cm and then she molds that cylinder into sphere. Find the volume of the cylindrical shape. (a) 288 π cm 3 (b) 244 π cm 3. (c) 240 π cm 3 (d) 216 π cm 3.

  21. Mensuration Class 8 Extra Questions Maths Chapter 11

    Mensuration Class 8 Extra Questions Short Answer Type. Question 11. The volume of a box is 13400 cm 3. The area of its base is 670 cm 2. Find the height of the box. Solution: Volume of the box = 13400 cm 3. Area of the box = 670 cm 2. Hence, the required height = 20 cm.

  22. CBSE Class 10 Maths Case Study Questions for Chapter 13

    The cloth require to cover the hemispherical dome if the radius of its base is 14m is. a) 1222 sq.m. b) 1232 sq.m. c) 1200 sq.m. d) 1400 sq.m. Answer: b) 1232 sq.m. 4. The total surface area of ...

  23. Mensuration Class 8 Notes

    Solved Questions for Mensuration Class 8. Example 1: Find the area of a square whose side is 30 m. Solution: The area of square = (Side) 2. Given, side = 30 m. Then, area of square = (30) 2 = 900 m 2. Example 2: Find the perimeter of a triangle with two equal sides of 5 cm and one side of 10 cm.

  24. CBSE 10th Standard Maths Surface Areas and Volumes Case Study Questions

    5. (a) Meera and Dhara have 12 and 8 coins respectively each of radius 3.5 cm and thickness 0.5 cm. They place their coins one above the other to form solid cylinders . Based on the above information, answer the following questions. (i) Curved surface area of the cylinder made by Meera is. (a) 144 cm2. (b) 132 cm2.