Gurukul of Excellence

Classes for Physics, Chemistry and Mathematics by IITians

Join our Telegram Channel for Free PDF Download

## Case Study Questions for Class 8 Maths

- Last modified on: 9 months ago
- Reading Time: 7 Minutes

Table of Contents

Here in this article, we are providing case study questions for class 8 maths.

## Maths Class 8 Chapter List

Latest chapter list (2023-24).

Chapter 1 Rational Numbers Chapter 2 Linear Equations in One Variable Chapter 3 Understanding Quadrilaterals Chapter 4 Data Handling Chapter 5 Squares and Square Roots Chapter 6 Cubes and Cube Roots Chapter 7 Comparing Quantities Chapter 8 Algebraic Expressions and Identities Chapter 9 Mensuration Chapter 10 Exponents and Powers Chapter 11 Direct and Indirect proportions Chapter 12 Factorisation Chapter 13 Introduction to Graphs

## Old Chapter List

Chapter 1 Rational Numbers Chapter 2 Linear Equations in One Variable Chapter 3 Understanding Quadrilaterals Chapter 4 Practical Geometry Chapter 5 Data Handling Chapter 6 Squares and Square Roots Chapter 7 Cubes and Cube Roots Chapter 8 Comparing Quantities Chapter 9 Algebraic Expressions and Identities Chapter 10 Visualising Solid Shapes Chapter 11 Mensuration Chapter 12 Exponents and Powers Chapter 13 Direct and Indirect proportions Chapter 14 Factorisation Chapter 15 Introduction to Graphs Chapter 16 Playing with Numbers

## Tips for Answering Case Study Questions for Class 8 Maths in Exam

1. Comprehensive Reading for Context: Prioritize a thorough understanding of the provided case study. Absorb the contextual details and data meticulously to establish a strong foundation for your solution.

2. Relevance Identification: Pinpoint pertinent mathematical concepts applicable to the case study. By doing so, you can streamline your thinking process and apply appropriate methods with precision.

3. Deconstruction of the Problem: Break down the complex problem into manageable components or steps. This approach enhances clarity and facilitates organized problem-solving.

4. Highlighting Key Data: Emphasize critical information and data supplied within the case study. This practice aids quick referencing during the problem-solving process.

5. Application of Formulas: Leverage pertinent mathematical formulas, theorems, and principles to solve the case study. Accuracy in formula selection and unit usage is paramount.

6. Transparent Workflow Display: Document your solution with transparency, showcasing intermediate calculations and steps taken. This not only helps track progress but also offers insight into your analytical process.

7. Variable Labeling and Definition: For introduced variables or unknowns, offer clear labels and definitions. This eliminates ambiguity and reinforces a structured solution approach.

8. Step Explanation: Accompany each step with an explanatory note. This reinforces your grasp of concepts and demonstrates effective application.

9. Realistic Application: When the case study pertains to real-world scenarios, infuse practical reasoning and logic into your solution. This ensures alignment with real-life implications.

10. Thorough Answer Review: Post-solving, meticulously review your answer for accuracy and coherence. Assess its compatibility with the case study’s context.

11. Solution Recap: Before submission, revisit your solution to guarantee comprehensive coverage of the problem and a well-organized response.

12. Previous Case Study Practice: Boost your confidence by practicing with past case study questions from exams or textbooks. This familiarity enhances your readiness for the question format.

13. Efficient Time Management: Strategically allocate time for each case study question based on its complexity and the overall exam duration.

14. Maintain Composure and Confidence: Approach questions with poise and self-assurance. Your preparation equips you to conquer the challenges presented.

## Download CBSE Books

Exam Special Series:

- Sample Question Paper for CBSE Class 10 Science (for 2024)
- Sample Question Paper for CBSE Class 10 Maths (for 2024)
- CBSE Most Repeated Questions for Class 10 Science Board Exams
- CBSE Important Diagram Based Questions Class 10 Physics Board Exams
- CBSE Important Numericals Class 10 Physics Board Exams
- CBSE Practical Based Questions for Class 10 Science Board Exams
- CBSE Important “Differentiate Between” Based Questions Class 10 Social Science
- Sample Question Papers for CBSE Class 12 Physics (for 2024)
- Sample Question Papers for CBSE Class 12 Chemistry (for 2024)
- Sample Question Papers for CBSE Class 12 Maths (for 2024)
- Sample Question Papers for CBSE Class 12 Biology (for 2024)
- CBSE Important Diagrams & Graphs Asked in Board Exams Class 12 Physics
- Master Organic Conversions CBSE Class 12 Chemistry Board Exams
- CBSE Important Numericals Class 12 Physics Board Exams
- CBSE Important Definitions Class 12 Physics Board Exams
- CBSE Important Laws & Principles Class 12 Physics Board Exams
- 10 Years CBSE Class 12 Chemistry Previous Year-Wise Solved Papers (2023-2024)
- 10 Years CBSE Class 12 Physics Previous Year-Wise Solved Papers (2023-2024)
- 10 Years CBSE Class 12 Maths Previous Year-Wise Solved Papers (2023-2024)
- 10 Years CBSE Class 12 Biology Previous Year-Wise Solved Papers (2023-2024)
- ICSE Important Numericals Class 10 Physics BOARD Exams (215 Numericals)
- ICSE Important Figure Based Questions Class 10 Physics BOARD Exams (230 Questions)
- ICSE Mole Concept and Stoichiometry Numericals Class 10 Chemistry (65 Numericals)
- ICSE Reasoning Based Questions Class 10 Chemistry BOARD Exams (150 Qs)
- ICSE Important Functions and Locations Based Questions Class 10 Biology
- ICSE Reasoning Based Questions Class 10 Biology BOARD Exams (100 Qs)

✨ Join our Online JEE Test Series for 499/- Only (Web + App) for 1 Year

✨ Join our Online NEET Test Series for 499/- Only for 1 Year

## 1 thought on “ Case Study Questions for Class 8 Maths ”

- Pingback: Case Study Questions for CBSE Class 8 Maths - ebookpublisher.in

## Leave a Reply Cancel reply

Join our Online Test Series for CBSE, ICSE, JEE, NEET and Other Exams

Editable Study Materials for Your Institute - CBSE, ICSE, State Boards (Maharashtra & Karnataka), JEE, NEET, FOUNDATION, OLYMPIADS, PPTs

## Discover more from Gurukul of Excellence

Subscribe now to keep reading and get access to the full archive.

Type your email…

Continue reading

- Saturday, May 18, 2024
- Privacy Policy
- Uncategorized

## Case Study- (Surface Areas and Volumes)

Surface Areas and Volumes

CASE STUDY 1:

Adventure camps are the perfect place for the children to practice decision making for themselves without parents and teachers guiding their every move. Some students of a school reached for adventure at Sakleshpur. At the camp, the waiters served some students with a welcome drink in a cylindrical glass and some students in a hemispherical cup whose dimensions are shown below. After that they went for a jungle trek. The jungle trek was enjoyable but tiring. As dusk fell, it was time to take shelter. Each group of four students was given a canvas of area 551m2 . Each group had to make a conical tent to accommodate all the four students. Assuming that all the stitching and wasting incurred while cutting, would amount to 1m2 , the students put the tents. The radius of the tent is 7m.

1. The volume of cylindrical cup is

a) 295.75 cm 3

b) 7415.5 cm 3

c) 384.88 cm 3

d) 404.25 cm 3

Answer: d) 404.25 cm 3

2. The volume of hemispherical cup is

a) 179.67 cm 3

b) 89.83 cm 3

c) 172.25 cm 3

d) 210.60 cm 3

Answer: b) 89.83 cm 3

3. Which container had more juice and by how much?

a) Hemispherical cup, 195 cm 3

b) Cylindrical glass, 207 cm 3

c) Hemispherical cup, 280.85 cm 3

d) Cylindrical glass, 314.42 cm 3

Answer: d) Cylindrical glass, 314.42 cm 3

4. The height of the conical tent prepared to accommodate four students is

Answer: c) 24m

5. How much space on the ground is occupied by each student in the conical tent

b) 38.5 m 2

Answer: b) 38.5 m 2

CASE STUDY 2:

The Great Stupa at Sanchi is one of the oldest stone structures in India, and an important monument of Indian Architecture. It was originally commissioned by the emperor Ashoka in the 3rd century BCE. Its nucleus was a simple hemispherical brick structure built over the relics of the Buddha. .It is a perfect example of combination of solid figures. A big hemispherical dome with a cuboidal structure mounted on it. (Take π = 22/7)

1. Calculate the volume of the hemispherical dome if the height of the dome is 21 m –

a) 19404 cu. m

b) 2000 cu .m

c) 15000 cu. m

d) 19000 cu. m

Answer: a) 19404 cu. m

2. The formula to find the Volume of Sphere is –

a) 2/3 πr 3

b) 4/3 πr 3

Answer: b) 4/3 πr 3

3. The cloth require to cover the hemispherical dome if the radius of its base is 14m is

a) 1222 sq.m

b) 1232 sq.m

c) 1200 sq.m

d) 1400 sq.m

Answer: b) 1232 sq.m

4. The total surface area of the combined figure i.e. hemispherical dome with radius 14m and cuboidal shaped top with dimensions 8m 6m 4m is

a)1200 sq. m

b) 1232 sq. m

c) 1392 sq.m

d) 1932 sq. m

Answer: c) 1392 sq.m

5. The volume of the cuboidal shaped top is with dimensions mentioned in question 4

a) 182.45 m 3

b) 282.45 m 3

Answer: d) 192 m 3

CASE STUDY 3:

On a Sunday, your Parents took you to a fair. You could see lot of toys displayed, and you wanted them to buy a RUBIK’s cube and strawberry ice-cream for you. Observe the figures and answer the questions:-

1. The length of the diagonal if each edge measures 6cm is

Answers: d) 6√3

2. Volume of the solid figure if the length of the edge is 7cm is

b) 196 cm 3

c) 343 cm 3

d) 434 cm 3

Answers: c) 343 cm 3

3. What is the curved surface area of hemisphere (ice cream) if the base radius is 7cm?

a) 309 cm 2

b) 308 cm 2

c) 803 cm 2

d) 903 cm 2

Answers: b) 308 cm 2

4. Slant height of a cone if the radius is 7cm and the height is 24 cm___

Answers: b) 25 cm

5. The total surface area of cone with hemispherical ice cream is

a) 858 cm 2

b) 885 cm 2

c) 588 cm 2

d) 855 cm 2

Answers: a) 858 cm 2

Based on the above information, answer the following questions.

(i) Find the lateral surface area of the Hermika, if the side of cubical part is 8 m.

(ii) The diameter and height of the cylindrical base part are respectively 42 m and 12 m. If the volume of each brick used is 0.01 m 3 , then find the number of bricks used to make the cylindrical base.

(a) 1663200

(b) 1580500

(c) 1765000

(d) 1865000

(iii) If the diameter of the Anda is 42 m, then the volume of the Anda is

(a) 17475 m 3

(b) 18605 m 3

(c) 19404 m 3

(d) 18650 m 3

(iv) The radius of the Pradakshina path is 25 m. If Buddhist priest walks 14 rounds on this path, then find the distance covered by the priest.

(v) The curved surface area of the Anda is

(a) 2856 m 2

(b) 2772 m 2

(c) 2473 m 2

(d) 2652 m 2

(i) After carving out cone from the cylinder,

(ii) Find the slant height of the conical cavity so formed.

(iii) The curved surface area of the conical cavity so formed is

(iv) External curved surface area of the cylinder is

(v) Volume of conical cavity is

(i) The radius of the sphere so formed is

(ii) The volume of the sphere so formed is

(iii) Find the ratio of the volume of sphere to the volume of cylinder.

(iv) Total surface area of the cylinder is

(v) During the conversion of a solid from one shape to another the volume of new shape will

(i) The volume of the cuboidal part is

(ii) Total volume of conical depressions is

(iii) Volume of the wood used in the entire stand is

(iv) Total surface area of cone of radius r is given by

( a ) π r l + π r ²

( b ) 2 π r l + π r²

( c ) π r 2 l + π r ²

( d ) π r l + 2 π r³

(v) If the cost of wood used is Rs 5 per cm 3 , then the total cost of making the pen stand is

(i) Curved surface area of the cylinder made by Meera is

(ii) The ratio of curved surface area of the cylinders made by Meera and Dhara is

(iii) The volume of the cylinder made by Dhara is

(iv) The ratio of the volume of the cylinders made by Meera and Dhara is

(v) When two coins are shifted from Meeras cylinder to Dhara’s cylinder, then

Case Study Questions

(i) (b) : Lateral surface area of Hermika which is cubical in shape = 4a 2 = 4 × (8) 2 = 256 m 2

= 44 × 21 × 21 = 19404 m 3

(i) (a) (ii) (d): Slant height of conical cavity l = h 2 + r 2

l = 25 c m

(iv) (c) : External curved surface area of cylinder = 2 π r h

(iii) (c): ∵ Volume of sphere = Volume of cylinder ∴ Required ratio = 1 : 1

(i) (b): Volume of cuboidal part = l x b x h

= (20 × 15 × 5) cm 3 = 1500 cm 3

(iii) (d): Volume of wood used in the entire stand = Volume of cuboidal part – Total volume of conical depressions = 1500 – 2.376 = 1497.624 cm 3

(v) (d): Cost of wood per cm 3 = Rs 5 ∴ Total cost of making the pen stand = Rs (5 x 1497.624)

= Rs 7488.12

## Leave a Reply Cancel reply

Your email address will not be published. Required fields are marked *

Save my name, email, and website in this browser for the next time I comment.

If you're seeing this message, it means we're having trouble loading external resources on our website.

If you're behind a web filter, please make sure that the domains *.kastatic.org and *.kasandbox.org are unblocked.

To log in and use all the features of Khan Academy, please enable JavaScript in your browser.

## Unit 13: Surface area and volume

Cube, cuboid, and cylinder.

- Surface area of a box (cuboid) (Opens a modal)
- Volume of a rectangular prism (Opens a modal)
- Cylinder volume & surface area (Opens a modal)
- Volume of rectangular prisms 7 questions Practice
- Volume of cylinders 4 questions Practice

Talk to our experts

1800-120-456-456

- RS Aggarwal Solutions Class 8 Chapter-20 Volume and Surface Area of Solids (Ex 20A) Exercise 20.1
- RS Aggarwal Solutions

## RS Aggarwal Solutions Class 8 Chapter-20 Volume and Surface Area of Solids (Ex 20A) Exercise 20.1 - Free PDF

The RS Aggarwal Class 8 Chapter 20 is important in the syllabus of Class 8. The PDF here is formulated to cover all the aspects of this Chapter and give a clear insight on how to learn the concepts and implement them in the questions. The experts at Vedantu have meticulously worked on this topic of RS Aggarwal Class 8 Chapter 20 Exercise 20A and came up with a short yet well-explained concept so that all the students can understand the concept easily and do not have any doubts further. Practice more questions from RS Aggarwal Class 8 Ex 20A for better scoring. Vedantu is a platform that provides free NCERT Solution and other study materials for students. You can also download NCERT Solution for Class 8 Science and NCERT Solutions for Class 8 Maths to help you to revise the complete syllabus and score more marks in your examinations.

## Class 8 RS Aggarwal Exercise 20A Free PDF Download

The RS Aggarwal Class 8 Ex 20A has all the information needed to solve the questions and will help you very much at the time of your examination. If the PDF of the RS Aggarwal Class 8 20A solution is downloaded, It will be available to you all the time and can come in handy whenever you want to revise the topic. For all the students who want to excel in the examination, the solutions can be of great help. The important points and the formulae are listed very precisely and clearly. Our PDF solutions help students to assess their understanding of the topic better.

## RS Aggarwal Class 8 Exercise 20A Solution

Chapter - surface area and volume.

The Surface Area and Volume Class 8 will cover the concepts of how to find the Volume and Surface Areas of certain solids. All the formulae related to the cube, cuboid, cylinder, cone, etc., are mentioned and the perfect examples illustrating these formulae are provided in a detailed manner. The main focus is on the Volume, lateral Surface Area, and total Surface Area. The application of using these formulae and finding the required elements is explained beautifully by our subject experts in the Surface Area and Volume Class 8.

## Why is RS Aggarwal Class 8 Chapter 20 Important?

The PDF covers all the important formulae of the questions asked in the exam.

Important points and topics are explained easily.

The concepts are very well explained by the subject matter experts which will make understanding effortless.

The PDF can be downloaded easily and this will make the article very handy for last-minute revision.

The important questions are prioritized and listed in this article.

Our solutions come with Chapter-wise strategies for students to prepare for exams.

Practising RS Aggarwal Class 8 Exercise 20A Solution will help you build conceptual knowledge about the subject.

## About the Chapter

This Chapter is primarily concerned with the Volumes and Surface Areas of a cuboid and a cube. Some applications of these formulae to simple problems from everyday life will be discussed as well. Students who are having difficulty solving problems can use RS Aggarwal Class 8. Our expert faculty team creates solutions with the utmost care to ensure that students understand the concepts clearly. Students can use the RD Sharma textbook as a reference source when studying for their board exams. This Chapter's solutions are available in PDF format and can be downloaded from the links provided below.

Volumes and Surface Areas of a Cuboid and a Cube Chapter 20 contains four exercises, and the RS Aggarwal Class 8 Solutions on this page provide answers to the questions in each exercise. Let's take a look at the concepts covered in this Chapter.

Regions of space.

The Volume of a body-formed space region.

A Volume unit that is universally accepted.

The formula for calculating a cuboid's Volume.

A cube's Volume is its Volume.

Other Volume units are commonly used.

A cuboid's and a cube's Surface Areas

The Surface Area of a room's walls.

Problems of various kinds.

Any three-dimensional geometrical shape's Surface Area and Volume are calculated. The Surface Area of a given object is the Area or region occupied by the object's Surface. Volume, on the other hand, is the amount of space available in an object.

There are various shapes and sizes in geometry, such as the sphere, cube, cuboid, cone, cylinder, and so on. Each shape has both a Surface Area and a Volume. However, in the case of two-dimensional figures such as squares, circles, rectangles, triangles, and so on, we can only measure the Area covered by these figures and no Volume is available. Let us now look at the Surface Area and Volume formulas for various 3D shapes.

## What Exactly is Surface Area?

The Area is the space occupied by a two-dimensional flat Surface. It is expressed in square units. Surface Area refers to the Area occupied by a three-dimensional object's outer Surface. It's also expressed in square units.

## In General, There are Two Kinds of Areas:

Surface area total.

Curved Surface Area/Lateral Surface Area

The total Surface Area includes the base(s) and the curved portion. It is the total Area covered by the object's Surface. If the shape has a curved Surface and a flat base, the total Area is the sum of the two Areas.

## The Surface Area that is Curved

The Area of only the curved part of the shape, excluding its base, is referred to as the curved Surface Area (s). For shapes such as a cylinder, it is also known as lateral Surface Area.

## What Exactly is Volume?

Volume is the amount of space that an object or substance takes up, measured in cubic units. Two-dimensional objects lack Volume and instead focus on the Area. The Volume of a circle, for example, cannot be found, but the Volume of a sphere can. Because a sphere is a three-dimensional shape, this is true.

## RS Aggarwal Solutions Class 8 Ex 20A Chapterwise Weightage

RS Aggarwal Class 8 Exercise 20A solution is an important Chapter from the exam point of view. The formula of Volume of solids, LSA, and TSA of solids will be asked in the very short answer type format. There will be questions to solve for radius, the height of solids by giving some information about the solid in the short-answer type questions. The long answer type questions will have questions that will be application-based and involve real-time examples related to the formulae mentioned in the Chapter. We can expect 5-6 questions from RS Aggarwal Class 8 Chapter 20. The best way to improve your Maths score is to practice all these Class 8 RS Aggarwal Exercise 20A Questions daily.

## FAQs on RS Aggarwal Solutions Class 8 Chapter-20 Volume and Surface Area of Solids (Ex 20A) Exercise 20.1

1. The length of a geometry box is 20 cm, its breadth is 5 cm, and has height of 1 cm. Find the volume of the geometry box.

The length of geometry box = 20 cm

The length of geometry box = 5 cm

The length of geometry box = 1 cm

The geometry box is in the shape of a cuboid.

So, the Volume of the geometry box is the same as the Volume of the cuboid.

The Volume of cuboid = lbh

Volume of geometry box = 20 cm * 5 cm * 1 cm = 100 cubic cm.

Hence, the Volume of the cuboid is 100 cubic cm.

2. A cheese cube has a length of 5 cm and is further cut into smaller cubes which have a volume of 1 cubic cm each. Find the number of such smaller cubes obtained.

Length of larger cube = 5cm

The Volume of cube = side 3

The Volume of the larger cube = 5 3 = 125 cubic cm.

Number of cubes obtained = (Volume of the larger cube)/(Volume of smaller cubes)

Number of cubes = 125/1 = 125

Hence, the number of cubes obtained after cutting them into smaller cubes is 125.

3. Where can I find useful Math study materials for Class 9?

Everything you need can be found on the Vedantu app or website. These resources are created by experts in the field, and the information is accurate and dependable. Students will be able to find revision notes, important questions, question papers, and much more! There are no fees or costs associated with these study materials. All students need to do is sign in, and then they can download whatever they want in pdf format. You can benefit from these free resources, which will undoubtedly help you ace your exams.

4. How can I do well in Class 8 Math?

The only way to do well in Class 9 Maths is to practise. Complete all of the Chapter exercises. This will enhance your problem-solving abilities as well as your speed and efficiency. Important formulas, definitions, and equations can be written down in a notebook and reviewed on a regular basis. Solve previous year's sample papers and question papers within a time limit. This will familiarise you with the paper pattern and question type, as well as help you improve your time management skills. Revise on a regular basis to ensure that you retain everything you've learned for a longer period of time.

5. A rectangular water reservoir contains 105 m 3 of water. Find the depth of the water in the reservoir if its base measures 12 m by 3.5 m.

Given details are,

The capacity of water reservoir = 105 m 3

Length of base of reservoir = 12 m

Width of base = 3.5 m

Let the depth of reservoir be ‘hm

l × b × h = 105

h = 105 / (l × b)

= 105 / (12×3.5)

∴ The depth of the reservoir is 2.5 m

- Mensuration
- Volume and Surface Area

## Class 8 NCERT (CBSE and ICSE) Volume and Surface Area

Student assignments, create unlimited student assignments., online practice, online tests, printable worksheets and tests.

## ICSE / ISC / CBSE Mathematics Portal for K12 Students

Mathematics made easy for school students.

Class 8 , Exercise 37 , Volume & Surface Area of Solid Surfaces

## Class 8: Volume and Surface Area of Solids – Exercise 37

Question 1. Find the volume, the total surface area and the lateral surface area of the cuboid having:

i) Area of walls excluding the doors are windows

Area of walls excluding the doors are windows

Multiplying the above three expressions we get

## Share this:

- Click to share on Twitter (Opens in new window)
- Click to share on Facebook (Opens in new window)

## Leave a Reply Cancel reply

Discover more from icse / isc / cbse mathematics portal for k12 students.

Subscribe now to keep reading and get access to the full archive.

Type your email…

Continue reading

## myCBSEguide

- Entrance Exam
- Competitive Exams
- ICSE & ISC
- Teacher Exams
- UP Board
- Uttarakhand Board
- Bihar Board
- Chhattisgarh Board
- Haryana Board
- Jharkhand Board
- MP Board
- Rajasthan Board
- Courses
- Test Generator
- Homework Help
- News & Updates

- Dashboard
- Mobile App (Android)
- Browse Courses
- New & Updates
- Join Us
- Login
- Register

No products in the cart.

- Homework Help
- Mathematics

## Case study questions for class 8 …

## CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

Posted by Ankita Sharma 2 years, 3 months ago

Related Questions

Posted by Aaradhya Jayaraj Ghadi 1 day, 3 hours ago

Posted by Shaurya Thakur 1 day, 20 hours ago

Posted by Shukriya Tiwari 3 days, 4 hours ago

Posted by Gayatri Devi 3 days, 16 hours ago

- Don't post personal information, mobile numbers and other details.
- Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
- Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
- Ask specific question which are clear and concise.

Posted by Sushmita Das 2 hours ago

Posted by Dinesh Kumar Singh Raj Pratap 3 days, 15 hours ago

Posted by Channabasappa A 16 hours ago

Posted by Abhay Pundir 1 day, 18 hours ago

Posted by Qudshiya Sayed an hour ago

Posted by Ankita Bora 1 day, 3 hours ago

Trusted by 1 Crore+ Students

## Test Generator

Create papers online. It's FREE .

## CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

## Download myCBSEguide App

All courses.

- Entrance Exams
- Competative Exams
- Teachers Exams
- Uttrakand Board
- Bihar Board
- Chhattisgarh Board
- Haryana Board
- Jharkhand Board
- Rajasthan Board

## Other Websites

- Examin8.com

## CBSE Courses

- CBSE Class 12
- CBSE Class 11
- CBSE Class 10
- CBSE Class 09
- CBSE Class 08
- CBSE Class 07
- CBSE Class 06
- CBSE Class 05
- CBSE Class 04
- CBSE Class 03
- CBSE Class 02
- CBSE Class 01

## CBSE Sample Papers

- CBSE Test Papers
- CBSE MCQ Tests
- CBSE 10 Year Papers
- CBSE Syllabus

## NCERT Solutions

- CBSE Revision Notes
- Submit Your Papers
- Terms of Service
- Privacy Policy
- NCERT Solutions for Class 12
- NCERT Solutions for Class 11
- NCERT Solutions for Class 10
- NCERT Solutions for Class 09
- NCERT Solutions for Class 08
- NCERT Solutions for Class 07
- NCERT Solutions for Class 06
- NCERT Solutions for Class 05
- NCERT Solutions for Class 04
- NCERT Solutions for Class 03
- CBSE Class 12 Sample Papers
- CBSE Class 11 Sample Papers
- CBSE Class 10 Sample Papers
- CBSE Class 09 Sample Papers
- CBSE Results | CBSE Datesheet

## Please Wait..

## Free Printable Surface Area Worksheets for 8th Class

Math teachers, discover a collection of free printable Surface Area worksheets tailored for Class 8 students. Enhance your lessons and help students explore the fascinating world of geometry with these comprehensive resources provided by Quizizz.

## Explore Surface Area Worksheets by Grades

- kindergarten

## Explore Other Subject Worksheets for class 8

- Social studies
- Social emotional
- Foreign language
- Reading & Writing

## Explore printable Surface Area worksheets for 8th Class

Surface Area worksheets for Class 8 are an essential tool for teachers to help their students master the concepts of geometry and area in math. These worksheets provide a variety of problems that cover different shapes and objects, allowing students to practice calculating surface area using the appropriate formulas. With a focus on Class 8 math curriculum, these worksheets are designed to challenge students and enhance their understanding of geometry, while also reinforcing their skills in solving problems related to area. Teachers can use these worksheets as in-class activities, homework assignments, or even as assessment tools to gauge their students' progress in mastering surface area concepts. Surface Area worksheets for Class 8 are a valuable resource for teachers looking to improve their students' math skills and understanding of geometry and area.

Quizizz is an excellent platform for teachers that not only offers Surface Area worksheets for Class 8 but also provides a wide range of other math and geometry resources. This interactive platform allows teachers to create engaging quizzes and games that can be used in the classroom or assigned as homework. With Quizizz, teachers can easily track their students' progress and identify areas where they may need additional support or practice. In addition to Surface Area worksheets for Class 8, Quizizz offers resources covering various topics in math, such as algebra, fractions, and measurement. Teachers can also find resources for other subjects, making Quizizz a one-stop-shop for all their educational needs. By incorporating Quizizz into their lesson plans, teachers can enhance their students' learning experience and help them excel in math, geometry, and area concepts.

## RS Aggarwal Solutions Class 8 Exercise 20A Chapter 20 Volume and Surface Area of Solids

Get Latest Edition of RS Aggarwal Solutions Class 8 Chapter 20 Volume and Surface Area of Solids Exercise 20A. Volume and Surface Area of Solids RS Aggarwal Class 8 Maths Solutions help you to revise the complete syllabus and score excellent marks.

## RS Aggarwal Solutions Class 8 Chapter 20 Ex 20A

Also, check the solutions of other exercises from below.

- Chapter 20 Volume and Surface Area of Solids Exercise 20A
- Chapter 20 Volume and Surface Area of Solids Exercise 20B
- Chapter 20 Volume and Surface Area of Solids Exercise 20C
- Chapter 20 Volume and Surface Area of Solids CCE Test Paper

## Leave a Comment Cancel Reply

Your email address will not be published. Required fields are marked *

Save my name, email, and website in this browser for the next time I comment.

- Bihar Board

## RBSE Result 2024

Srm university.

- Goa Board Result 2024
- Maharashtra HSC Result
- Maharashtra SSC Result
- RBSE 10th Result 2024
- RBSE 12th Result 2024
- CBSE Board Result 2024
- Shiv Khera Special
- Education News
- Web Stories
- Current Affairs
- नए भारत का नया उत्तर प्रदेश
- School & Boards
- College Admission
- Govt Jobs Alert & Prep
- GK & Aptitude
- CBSE Class 10 Study Material

## CBSE Class 10 Maths Case Study Questions for Chapter 13 - Surface Areas and Volumes (Published By CBSE)

Check case study questions for cbse class 10 maths chapter 13 - surface areas and volumes. this question bank based on case study has been published by the board for class 10 mathematics..

Case study questions for CBSE Class 10 Maths Chapter 13 - Surface Areas and Volumes are published by the CBSE board. Students can solve these questions to acquaint themselves with the new type of questions. Answers to all the questions have been provided with them. These case study questions are quite helpful to prepare for the CBSE Class 10 Maths Exam 2021-2022.

Case Study Questions for Class 10 Maths Chapter 10 - Surface Areas and Volumes

CASE STUDY 1:

Adventure camps are the perfect place for the children to practice decision making for themselves without parents and teachers guiding their every move. Some students of a school reached for adventure at Sakleshpur. At the camp, the waiters served some students with a welcome drink in a cylindrical glass and some students in a hemispherical cup whose dimensions are shown below. After that they went for a jungle trek. The jungle trek was enjoyable but tiring. As dusk fell, it was time to take shelter. Each group of four students was given a canvas of area 551m2 . Each group had to make a conical tent to accommodate all the four students. Assuming that all the stitching and wasting incurred while cutting, would amount to 1m2 , the students put the tents. The radius of the tent is 7m.

1. The volume of cylindrical cup is

a) 295.75 cm 3

b) 7415.5 cm 3

c) 384.88 cm 3

d) 404.25 cm 3

Answer: d) 404.25 cm 3

2. The volume of hemispherical cup is

a) 179.67 cm 3

b) 89.83 cm 3

c) 172.25 cm 3

d) 210.60 cm 3

Answer: b) 89.83 cm 3

3. Which container had more juice and by how much?

a) Hemispherical cup, 195 cm 3

b) Cylindrical glass, 207 cm 3

c) Hemispherical cup, 280.85 cm 3

d) Cylindrical glass, 314.42 cm 3

Answer: d) Cylindrical glass, 314.42 cm 3

4. The height of the conical tent prepared to accommodate four students is

Answer: c) 24m

5. How much space on the ground is occupied by each student in the conical tent

b) 38.5 m 2

Answer: b) 38.5 m 2

CASE STUDY 2:

The Great Stupa at Sanchi is one of the oldest stone structures in India, and an important monument of Indian Architecture. It was originally commissioned by the emperor Ashoka in the 3rd century BCE. Its nucleus was a simple hemispherical brick structure built over the relics of the Buddha. .It is a perfect example of combination of solid figures. A big hemispherical dome with a cuboidal structure mounted on it. (Take π = 22/7)

1. Calculate the volume of the hemispherical dome if the height of the dome is 21 m –

a) 19404 cu. m

b) 2000 cu .m

c) 15000 cu. m

d) 19000 cu. m

Answer: a) 19404 cu. m

2. The formula to find the Volume of Sphere is -

a) 2/3 πr 3

b) 4/3 πr 3

c) 4 πr 2

d) 2 πr 2

Answer: b) 4/3 πr 3

3. The cloth require to cover the hemispherical dome if the radius of its base is 14m is

a) 1222 sq.m

b) 1232 sq.m

c) 1200 sq.m

d) 1400 sq.m

Answer: b) 1232 sq.m

4. The total surface area of the combined figure i.e. hemispherical dome with radius 14m and cuboidal shaped top with dimensions 8m 6m 4m is

a)1200 sq. m

b) 1232 sq. m

c) 1392 sq.m

d) 1932 sq. m

Answer: c) 1392 sq.m

5. The volume of the cuboidal shaped top is with dimensions mentioned in question 4

a) 182.45 m 3

b) 282.45 m 3

Answer: d) 192 m 3

CASE STUDY 3:

On a Sunday, your Parents took you to a fair. You could see lot of toys displayed, and you wanted them to buy a RUBIK’s cube and strawberry ice-cream for you. Observe the figures and answer the questions:-

1. The length of the diagonal if each edge measures 6cm is

a) 3√3

b) 3√6

c) √12

d) 6√3

Answers: d) 6√3

2. Volume of the solid figure if the length of the edge is 7cm is

b) 196 cm 3

c) 343 cm 3

d) 434 cm 3

Answers: c) 343 cm 3

3. What is the curved surface area of hemisphere (ice cream) if the base radius is 7cm?

a) 309 cm 2

b) 308 cm 2

c) 803 cm 2

d) 903 cm 2

Answers: b) 308 cm 2

4. Slant height of a cone if the radius is 7cm and the height is 24 cm___

Answers: b) 25 cm

5. The total surface area of cone with hemispherical ice cream is

a) 858 cm 2

b) 885 cm 2

c) 588 cm 2

d) 855 cm 2

Answers: a) 858 cm 2

Also Check:

CBSE Class 10 Maths Case Study Questions - All Chapters

Tips to Solve Case Study Based Questions Accurately

Get here latest School , CBSE and Govt Jobs notification in English and Hindi for Sarkari Naukari and Sarkari Result . Download the Jagran Josh Sarkari Naukri App . Check Board Result 2024 for Class 10 and Class 12 like CBSE Board Result , UP Board Result , Bihar Board Result , MP Board Result , Rajasthan Board Result and Other States Boards.

- JAC 9th, 11th रिजल्ट 2024
- JAC 9th रिजल्ट 2024
- JAC Result 2024
- jac.jharkhand.gov.in 11th Result 2024
- JAC 11वीं रिजल्ट 2024 रोल नंबर
- GBSHSE SSC Result 2024
- SSC Result 2024 Goa
- CDS 2 Notification 2024
- results.gbshsegoa.net Result 2024
- CBSE 10th Result 2024
- CBSE Study Material
- CBSE Class 10

## Latest Education News

JAC 8th Result 2024: झारखंड बोर्ड क्लास 8वीं का रिजल्ट jacresults.com पर जल्द, इस Website पर मिलेगा Direct Link

[रिजल्ट लिंक] JAC Result 2024 LIVE: Jharkhand Board 8th Result Soon, 9th, 11th Declared at jacresults.com, Check Marks Online by Roll Number, Roll Code

[डायरेक्ट लिंक] jac.jharkhand.gov.in 9th, 11th Result 2024: झारखंड बोर्ड 9वीं, 11वीं का रिजल्ट jacresults.com पर जारी, यहां Roll Number से तुुरंत करें चेक

NEET Paper Leak 2024: SC Rejects Plea to Halt Results Despite Alleged Leak, Check Details

[रिजल्ट लिंक] JAC 9th Result 2024 OUT: कोडरमा जिला रहा अव्वल, jac.jharkhand.gov.in पर Result Link से तुरंत डाउनलोड करें Marksheet

[Fast Update] IPL Points Table 2024: आईपीएल 2024 अपडेटेड पॉइंट टेबल यहां देखें, KKR और RR, SRH Qualify

IPL 2024 RCB Players: रॉयल चैलेंजर्स बेंगलूरू के खिलाड़ियों की पूरी लिस्ट यहां देखें Today RCB vs CSK मैच

IPL 2024 Stats: आईपीएल में किसने फेंकी थी पहली गेंद, किसने लिया पहला विकेट और किसने जड़ा पहला छक्का

IPL 2024 Playoffs Teams: इन 4 टीमों का प्लेऑफ टिकट कन्फर्म! KKR, SRH और RR के बाद किसका नंबर

IPL 2024 Qualifier, Eliminator: कब, कहां और किसके बीच होगा क्वालीफायर और एलिमिनेटर, Tickets और Live Streaming कैसे देखें

IPL 2024 Live Streaming: मोबाइल या टीवी कहां और कैसे देखें आज के आईपीएल का LIVE टेलीकास्ट?

IPL 2024 Full Schedule: आईपीएल 2024 का फुल शेड्यूल,आज किस टीम का है मैच जानें यहां

ICC T20 World Cup 2024: T20 वर्ल्ड कप का शेड्यूल जारी, कब और किससे है India का Match देखें यहां

IPL 2024 CSK Players: चेन्नई सुपर किंग्स के खिलाड़ियों की पूरी लिस्ट यहां देखें, धोनी-कोहली की विराट टक्कर

Find 3 Differences In 27 Seconds In This Bird Watching Scene

बिहार एसटीईटी अपेक्षित कट ऑफ 2024: केटेगरी वाइज कट ऑफ यहाँ देखें

बिहार एसटीईटी परीक्षा विश्लेषण May 18, 2024: पेपर 1 रिव्यु, पेपर समीक्षा, स्तर और प्रयास

Bihar STET 2024 Exam Analysis, May 18: Check Paper Review, Difficulty Level, Good Attempts

Updated CSK vs RCB Head to Head in IPL: Check Stats, Records and Results

Today’s IPL Match (18 May) - RCB vs CSK: Team Squad, Match Time, Where to Watch Live and Stadium

- Math Article

## Mensuration Class 8

Mensuration Class 8 Chapter 11 notes, important questions and formulas are mentioned here. Class 8 Chapter 11 Mensuration materials are provided here as per CBSE syllabus (2022-2023) and latest exam pattern. Get through the formulas and practise the concept of mensuration with the help of given examples. Mensuration chapter has been further introduced in Class 10, hence it is necessary that each student learns its basic concept first. Mensuration basically means the measurement of the area and perimeter of different geometrical shapes such as triangles, trapeziums, rectangles, etc. Preparing this chapter from this article will help students in scoring good marks in the final exams.

## Mensuration Class 8 Notes

Mensuration deals with the measurement of area, perimeter, surface area and volume of different types of shapes.

Let us recall the area of all two-dimensional shapes.

## Mensuration Class 8 – Area of Trapezium

By constructing EC || AB, we can split the given figure (AEDCBA) into two parts (Triangle ECD right-angled at C and Rectangle AECB), Here, b = a + c = 30 m

Now, Area of Triangle DCE:

1/2 × CD × EC= 1/2 × c × s

h = 1/2 ×10× 12 = 60 m 2

Also, Area of rectangle AECB = AB × BC = h × a=12 × 20=240 m 2

Therefore, Area of trapezium AEDB = Area of Triangle DCE + Area of rectangle AECB = 60 + 240 = 300 =300m 2

Area of Trapezium = Height/2 (Sum of parallel sides) = 1/2 h(a+b)

## Mensuration Class 8 – Area of General Quadrilateral

Diagonal AC divides the given quadrilateral into two triangles i.e. Triangle ABC and Triangle ADC.

Now, Area of Quadrilateral ABCD = Area of Triangle ABC + Area of Triangle ADC.

=1/2 × AC × h 1 + 1/2 × AC × h 2 =1/2 × d × (h 1 +h 2 )

Where, d = The length of diagonal of a quadrilateral.

The area of other polygons (pentagon, hexagon, etc.) can be determined, by splitting them into a number of triangles and finding the respective areas.

## Mensuration Class 8 Formulas

The important formulas covered in this chapter are as follows:

- d1 and d2 are the diagonals of the rhombus
- d is the diagonal of a special quadrilateral which is divided into two triangles
- h 1 and h 2 are the two perpendiculars from the vertices of a quadrilateral to its diagonal
- l, b and h denotes length, breadth and height of the cuboid
- r represents the radius of the cylindrical base
- a is the side of the cube

## Class 8 Mensuration Important Points

- The trapezium and rhombus are the figures represented in the two-dimensional plane. Whereas Cuboid, Cube and Cylinder are three-dimensional solid shape.
- The surface area of a solid shape is the sum of the areas of its faces.
- Amount of region occupied by a solid shape is called its volume.

## Volume and Capacity

Volume and capacity are almost similar to each other.

- A volume is the amount of space occupied by a three-dimensional object
- Capacity is the quantity of liquid contained in an object
- 1 mL = 1 cm 3
- 1 L = 1000 cm 3
- 1 m 3 = 1000000 cm 3 = 1000 L

## More Articles for Class 8

Solved questions for mensuration class 8.

Example 1: Find the area of a square whose side is 30 m.

Solution: The area of square = (Side) 2

Given, side = 30 m.

Then, area of square = (30) 2 = 900 m 2 .

Example 2: Find the perimeter of a triangle with two equal sides of 5 cm and one side of 10 cm.

Solution: We know that,

perimeter of triangle = sum of all the three sides

= (5 + 5 + 10)

Example 3: Calculate the area of a trapezium whose height is 4 cm and length of parallel sides are 5 cm and 3 cm, respectively. Solution: Given, Height of the trapezium = 4cm and length of parallel sides are 5cm and 3cm respectively.

Area of trapezium = height x (sum of parallel sides)/2

A = 4 x (5 + 3)/2

A = 4 x 8/2

A = 16 sq.cm.

Example 4: Find the area of special quadrilateral whose diagonal length is 6 cm. And the lengths of two perpendiculars on given diagonal from the vertices are 3 cm and 4 cm.

Solution: Given, diagonal of quadrilateral, d = 6 cm.

Let the length of two perpendiculars be h 1 = 3 cm and h 2 = 4 cm.

As per the formula of quadrilateral, we can write,

Area of quadrilateral ABCD = ½ x d x (h 1 + h 2 )

A = 1/2 x 6 x (3 + 4)

= 1/2 x 6 x 7

Example 5: Find the area of rhombus in which the length of its two diagonals is 8.5cm and 10 cm.

Solution: We know;

Area of rhombus = ½ x d 1 x d 2

A = 1/2 x 8.5 x 10

A = 42.5 sq.cm.

## Frequently Asked Questions on Mensuration Class 8

How many cubic centimetres make 1 litre.

1 litre = 1000 cm 3 and 1 millilitre = 1 cm 3 .

## What is the curved surface area of a cylinder?

The curved surface area of a cylinder is given by 2𝜋rh square units, where r is the radius of circular ends and h is the height of the cylinder.

## What is the area of a special quadrilateral?

The area of a special quadrilateral is given by ½ x d x (h 1 + h 2 ) square units, where d is the diagonal which divided the quadrilateral into two triangles and h 1 , h 2 are the two perpendiculars from the vertices of a quadrilateral to its diagonal.

## What is the area of a parallelogram?

The area of a parallelogram is given by b × h, where h is the altitude of the parallelogram on the base b.

Put your understanding of this concept to test by answering a few MCQs. Click ‘Start Quiz’ to begin!

Select the correct answer and click on the “Finish” button Check your score and answers at the end of the quiz

Visit BYJU’S for all Maths related queries and study materials

Your result is as below

Request OTP on Voice Call

## Leave a Comment Cancel reply

Your Mobile number and Email id will not be published. Required fields are marked *

Post My Comment

Your website is wery useful. It helped me a lot for maths

Thank you Byjus!

Thank you byjus! For clarafing my doubt ,now I am not worried about my exam😀

It was very useful for a quick revision and the examples made me clear my doubts Thank you byjus

- Share Share

## Register with BYJU'S & Download Free PDFs

Register with byju's & watch live videos.

- New QB365-SLMS
- NEET Materials
- JEE Materials
- Banking first yr Materials
- TNPSC Materials
- DIPLOMA COURSE Materials
- 5th Standard Materials
- 12th Standard Materials
- 11th Standard Materials
- 10th Standard Materials
- 9th Standard Materials
- 8th Standard Materials
- 7th Standard Materials
- 6th Standard Materials
- 12th Standard CBSE Materials
- 11th Standard CBSE Materials
- 10th Standard CBSE Materials
- 9th Standard CBSE Materials
- 8th Standard CBSE Materials
- 7th Standard CBSE Materials
- 6th Standard CBSE Materials
- Tamilnadu Stateboard
- Scholarship Exams
- Scholarships

## CBSE 10th Standard Maths Subject Surface Areas and Volumes Case Study Questions 2021

By QB365 on 22 May, 2021

QB365 Provides the updated CASE Study Questions for Class 10 Maths, and also provide the detail solution for each and every case study questions . Case study questions are latest updated question pattern from NCERT, QB365 will helps to get more marks in Exams

## QB365 - Question Bank Software

10th Standard CBSE

Final Semester - June 2015

Case Study Questions

(ii) The diameter and height of the cylindrical base part are respectively 42 m and 12 m. If the volume of each brick used is 0.01 m 3 , then find the number of bricks used to make the cylindrical base.

(iii) If the diameter of the Anda is 42 m, then the volume of the Anda is

(iv) The radius of the Pradakshina path is 25 m. If Buddhist priest walks 14 rounds on this path, then find the distance covered by the priest.

(v) The curved surface area of the Anda is

(ii) Find the slant height of the conical cavity so formed.

(iii) The curved surface area of the conical cavity so formed is

(iv) External curved surface area of the cylinder is

(v) Volume of conical cavity is

(ii) The volume of the sphere so formed is

(iii) Find the ratio of the volume of sphere to the volume of cylinder.

(iv) Total surface area of the cylinder is

(v) During the conversion of a solid from one shape to another the volume of new shape will

(ii) Total volume of conical depressions is

(iii) Volume of the wood used in the entire stand is

(iv) Total surface area of cone of radius r is given by

(v) If the cost of wood used is Rs 5 per cm 3 , then the total cost of making the pen stand is

(ii) The ratio of curved surface area of the cylinders made by Meera and Dhara is

(iii) The volume of the cylinder made by Dhara is

(iv) The ratio of the volume of the cylinders made by Meera and Dhara is

(v) When two coins are shifted from Meeras cylinder to Dhara's cylinder, then

## *****************************************

Cbse 10th standard maths subject surface areas and volumes case study questions 2021 answer keys.

(i) (b) : Lateral surface area of Hermika which is cubical in shape = 4a 2 = 4 x (8) 2 = 256 m 2 (ii) (a) : Diameter of cylindrical base = 42 m \(\therefore\) Radius of cylindrical base (r) = 21 m Height of cylindrical base (h) = 12 m \(\therefore\) Number of bricks used \(=\frac{\frac{22}{7} \times 21 \times 21 \times 12}{0.01}\) = 1663200 (iii) (c) : Given, diameter of Anda which is hemispherical in shape = 42 m \(\Rightarrow\) Radius of Anda (r) = 21 m \(\therefore \quad \text { Volume of } A n d a =\frac{2}{3} \pi r^{3}=\frac{2}{3} \times \frac{22}{7} \times 21 \times 21 \times 21 \) \(=44 \times 21 \times 21=19404 \mathrm{~m}^{3}\) (iv) (d): Given, radius of Pradakshina Path (r) = 25 m \(\therefore\) Perimeter of path = \(2\pi r\) \(=\left(2 \times \frac{22}{7} \times 25\right) \mathrm{m}\) · . Distance covered by priest \(=14 \times 2 \times \frac{22}{7} \times 25\) = 2200 m (v) (b): \(\because\) Radius of Anda (r) = 21 m \(\therefore\) Curved surface area of Anda = \(2\pi r^{2}\) \(=2 \times \frac{22}{7} \times 21 \times 21=2772 \mathrm{~m}^{2}\)

(i) (a) (ii) (d): Slant height of conical cavity \(l=\sqrt{h^{2}+r^{2}}\) \(=\sqrt{(24)^{2}+(7)^{2}}=\sqrt{576+49}=\sqrt{625}=25 \mathrm{~cm}\) (iii) (b): Curved surface area of conical cavity = \(\pi r l\) \(=\frac{22}{7} \times 7 \times 25=550 \mathrm{~cm}^{2}\) (iv) (c) : External curved surface area of cylinder \(=2 \pi r h=2 \times \frac{22}{7} \times 7 \times 24=1056 \mathrm{~cm}^{2}\) (v) (a): Volume of conical cavity \(=\frac{1}{3} \pi r^{2} h\) \(=\frac{1}{3} \times \frac{22}{7} \times 7 \times 7 \times 24=1232 \mathrm{~cm}^{3}\)

(i) (b): Since, volume of sphere = volume of cylinder \(\Rightarrow \frac{4}{3} \pi R^{3}=\pi r^{2} h\) where R, r are the radii of sphere and cylinder respectively. \(\Rightarrow R^{3}=\frac{6 \times 6 \times 8 \times 3}{4}=(6)^{3} \Rightarrow R=6 \mathrm{~cm}\) \(\therefore\) Radius of sphere = 6 cm (ii) (a): Volume of sphere \(=\frac{4}{3} \pi R^{3}\) \(=\frac{4}{3} \times \frac{22}{7} \times 6 \times 6 \times 6=905.14 \mathrm{~cm}^{3}\) (iii) (c): \(\because\) Volume of sphere = Volume of cylinder \(\therefore\) Required ratio = 1 : 1 (iv) (a): Total surface area of the cylinder \(=2 \pi r(r+h)\) \(=2 \times \frac{22}{7} \times 6(6+8)=2 \times \frac{22}{7} \times 6 \times 14=528 \mathrm{~cm}^{2}\) (v) (c)

(i) (b): Volume of cuboidal part = 1 x b x h = (20 x 15 x 5) cm 3 = 1500 cm 3 (ii) (c): Radius of conical depression, r = 0.6 cm Height of conical depression, h = 2.1 cm \(\therefore\) Total volume of conical depressions \(=3 \times \frac{1}{3} \pi r^{2} h\) \(=\frac{22}{7} \times 0.6 \times 0.6 \times 2.1=\frac{2.376}{1000}-2.376 \mathrm{~cm}^{3}\) (iii) (d): Volume of wood used in the entire stand = Volume of cuboidal part - Total volume of conical depressions = 1500 - 2.376 = 1497.624 cm 3 (iv) (a) (v) (d): Cost of wood per cm 3 = Rs 5 \(\therefore\) Total cost of making the pen stand = Rs (5 x 1497.624) = Rs 7488.12

We have, radius of each coin = 3.5 cm \(=\frac{35}{10} \mathrm{~cm}=\frac{7}{2} \mathrm{~cm}\) Thickness of each coin \(=0.5 \mathrm{~cm}=\frac{1}{2} \mathrm{~cm}\) So,height of cylinder made by Meera (h1) \(=12 \times \frac{1}{2}=6 \mathrm{~cm}\) and height of cylinder made by Dhara (h2) \(=8 \times \frac{1}{2}=4 \mathrm{~cm}\) (i) (b): Curved surface area of cylinder made by Meera \(=2 \times \frac{22}{7} \times \frac{7}{2} \times 6=132 \mathrm{~cm}^{2}\) (ii) (b): Required ratio \(=\frac{\text { Curved surface area of cylinder made by Meera }}{\text { Curved surface area of cylinder made by Dhara }}\) \(=\frac{2 \pi r h_{1}}{2 \pi r h_{2}}=\frac{h_{1}}{h_{2}}=\frac{6}{4}=\frac{3}{2} \text { i.e., } 3: 2\) (iii) (a): Volume of cylinder made by Dhara \(=\pi r^{2} h_{2}\) \(=\frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} \times 4=154 \mathrm{~cm}^{3}\) (iv) (c): Required ratio \(=\frac{\text { Volume of cylinder made by Meera }}{\text { Volume of cylinder made by Dhara }} \) \(=\frac{\pi r^{2} h_{1}}{\pi r^{2} h_{2}}=\frac{h_{1}}{h_{2}}=\frac{6}{4}=\frac{3}{2} \text { i.e., } 3: 2\) (v) (a): When two coins are shifted from Meera's cylinder to Dhara's cylinder, then length of both cylinders become equal. So, volume of both cylinders become equal

## Related 10th Standard CBSE Maths Materials

10th standard cbse syllabus & materials, cbse 10th social science the making of a global world chapter case study question with answers, cbse 10th social science nationalism in india chapter case study question with answers, cbse 10th social science the rise of nationalism in europe chapter case study question with answers, cbse 10th science metals and non metals chapter case study question with answers, cbse 10th science acids, bases and salts chapter case study question with answers, cbse 10th science chemical reactions and equations chapter case study question with answers, class 10th science - our environment case study questions and answers 2022 - 2023, class 10th science - magnetic effects of electric current case study questions and answers 2022 - 2023, class 10th science - electricity case study questions and answers 2022 - 2023, class 10th science - human eye and the colourful world case study questions and answers 2022 - 2023, class 10th science - light reflection and refraction case study questions and answers 2022 - 2023, class 10th science - heredity and evolution case study questions and answers 2022 - 2023, class 10th science - how do organisms reproduce case study questions and answers 2022 - 2023, class 10th science - life processes case study questions and answers 2022 - 2023, class 10th science - periodic classification of elements case study questions and answers 2022 - 2023.

## Class VI to XII

Tn state board / cbse, 3000+ q&a's per subject, score high marks.

## IMAGES

## VIDEO

## COMMENTS

Case Study Class 8 Surface Area and Volumes | I Did It Mathematics Class 8 | Anupama Rathi-----...

∴ Ratio of their curved surface area is 10:9. 8. The ratio between the curved surface area and the total surface area of a right circular cylinder is 1:2. Prove that its height and radius are equal. Solution: We have, Let radius of cylinder be 'r' Let height of cylinder be 'h' Curved surface area of cylinder / total surface area of ...

a) volume b)lateral surface area. c) total surface area d)none of these. 5. The volume of a cuboid whose length, breadth and height are 2a, 3a and 4a is. a) b)24a3 c)12a3 d)none of these. 6. The curved surface area of a right circular cylinder of radius 2r and height 2h is. a) b)4Πrh c)8Πrh d)none of these. 7.

12. Previous Case Study Practice: Boost your confidence by practicing with past case study questions from exams or textbooks. This familiarity enhances your readiness for the question format. 13. Efficient Time Management: Strategically allocate time for each case study question based on its complexity and the overall exam duration. 14.

SURFACE AREA AND VOLUME (EX-13.2)Class-9th; SURFACE AREA AND VOLUME EXERCISE 13.3; ... Surface Areas and Volumes . CASE STUDY 1: ... answer the following questions. (i) Curved surface area of the cylinder made by Meera is (a) 144 cm 2 (b) 132 cm 2 (c) 154 cm 2 (d) 142 cm 2

Free PDF download of Important Questions with solutions for CBSE Class 8 Maths Chapter 11 - Mensuration prepared by expert Mathematics teachers from latest edition of CBSE(NCERT) books. ... Math is a tricky subject to study, and thus having proper notes can boost up the studying procedure and eventually your grades. ... Volume (b) Surface area ...

Class 8. 14 units · 61 skills. Unit 1. Rational and irrational numbers. Unit 2. Parallel lines and transversal. ... Cylinder volume & surface area (Opens a modal) Practice. Volume of rectangular prisms. 7 questions. Practice. Volume of cylinders. 4 questions. Practice. Our mission is to provide a free, world-class education to anyone, anywhere.

Chapter 21- Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) contains four exercises, and the RD Sharma Class 8 Solutions present in this page provide solutions to the questions given in each exercise. Now, let us have a look at the concepts discussed in this chapter.

If, on the other hand, we want to store milk or water in a container or food grains in a godown, we'll need to calculate the volume. All the Exercise questions with solutions in Chapter-20 Volume and Surface Area of Solids are given below: Exercise (Ex 20A) 20.1. Exercise (Ex 20B) 20.2. Exercise (Ex 20C) 20.3.

Free PDF download of RS Aggarwal Solutions Class 8 Chapter-20 Volume and Surface Area of Solids (Ex 20A) Exercise 20.1 solved by Expert Mathematics Teachers on Vedantu.com. All Exercise 20.1 Questions with Solutions for Class 8 RS Aggarwal to help you to revise complete Syllabus and Score More marks.

Surface Area and Volume of Cylinder ,Mensuration - Get topics notes, Online test, Video lectures, Doubts and Solutions for CBSE Class 8 on TopperLearning.

Curved surface area of cylinder. = 2πr x h. Volume of cuboid. = l x b x h. Volume of cube. =s³. Volume of cylinder. = πr²h. Study with Quizlet and memorize flashcards containing terms like Surface area of cuboid, Surface area of cube, Surface area of cylinder and more.

Volume and Surface Area problems, practice, tests, worksheets, questions, quizzes, teacher assignments | Class 8 | NCERT (CBSE and ICSE)

Question 5. Find the volume and total surface area of a cube whose edge is: (i) 8 cm. Solution:-Edge of the given cube =8cm. We know that (ii) 2m 40 cm. Solution:-(ii)Edge of the given cube =2 m 40 cm=2.40 m. We know that. Question 6. Find the length of each edge of a cube, if its volume is: Question 7. The total surface area of a cube is 216 ...

Volume of a cuboid . Question 8. The volume of the cuboid is . Its length is and its breadth and height Are in the ratio of . Find the breadth and height of the cube. Answer: Volume of a cuboid . Question 9. The surface area of the cuboid is . Its length and breadth are respectively. Find its height. Answer: Surface Area of a cuboid . Question 10.

CBSE, JEE, NEET, CUET. Question Bank, Mock Tests, Exam Papers. NCERT Solutions, Sample Papers, Notes, Videos. Install Now. Case study questions for class 8 topic surface area and volume and understanding quadrilaterals. Report. Posted by Ankita Sharma 2 years, 3 months ago. CBSE > Class 09 > Mathematics. 0 answers.

Surface Area And Volume III 10 Q. 8th - 10th Surface Areas 9 Q. 8th - 10th Surface Area of Prisms 11 Q. 7th - 8th Surface Area of Prisms 12 Q. 4th - 8th ... In addition to Surface Area worksheets for Class 8, Quizizz offers resources covering various topics in math, such as algebra, fractions, and measurement. ...

RS Aggarwal Solutions Class 8 Chapter 20 Ex 20A. Also, check the solutions of other exercises from below. Chapter 20 Volume and Surface Area of Solids Exercise 20A. Chapter 20 Volume and Surface Area of Solids Exercise 20B. Chapter 20 Volume and Surface Area of Solids Exercise 20C. Chapter 20 Volume and Surface Area of Solids CCE Test Paper.

Class 9th Maths - Surface Case Study Questions and Answers 2022 - 2023. QB365 provides a detailed and simple solution for every Possible Case Study Questions in Class 9th Maths Subject - Surface, CBSE. It will help Students to get more practice questions, Students can Practice these question papers in addition to score best marks.

Case Study/Passage-Based Questions. Case Study 1: A class teacher brings some clay in the classroom to teach the topic of mensuration. First she forms a cylinder of radius 6 cm and height 8 cm and then she molds that cylinder into sphere. Find the volume of the cylindrical shape. (a) 288 π cm 3 (b) 244 π cm 3. (c) 240 π cm 3 (d) 216 π cm 3.

Mensuration Class 8 Extra Questions Short Answer Type. Question 11. The volume of a box is 13400 cm 3. The area of its base is 670 cm 2. Find the height of the box. Solution: Volume of the box = 13400 cm 3. Area of the box = 670 cm 2. Hence, the required height = 20 cm.

The cloth require to cover the hemispherical dome if the radius of its base is 14m is. a) 1222 sq.m. b) 1232 sq.m. c) 1200 sq.m. d) 1400 sq.m. Answer: b) 1232 sq.m. 4. The total surface area of ...

Solved Questions for Mensuration Class 8. Example 1: Find the area of a square whose side is 30 m. Solution: The area of square = (Side) 2. Given, side = 30 m. Then, area of square = (30) 2 = 900 m 2. Example 2: Find the perimeter of a triangle with two equal sides of 5 cm and one side of 10 cm.

5. (a) Meera and Dhara have 12 and 8 coins respectively each of radius 3.5 cm and thickness 0.5 cm. They place their coins one above the other to form solid cylinders . Based on the above information, answer the following questions. (i) Curved surface area of the cylinder made by Meera is. (a) 144 cm2. (b) 132 cm2.